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Viktor [21]
4 years ago
15

It costs a bicycle company $40 to make each adult bicycle and $30 to make each child's bicycle. The adult bicycle sells for $120

, and the child's bicycle sells for $90. The company wants to make a minimum profit of $2,400. If x represents the number of adult bicycles the company sells, and y represents the number of children's bicycles the company sells, which inequality models this situation?
Mathematics
2 answers:
djyliett [7]4 years ago
8 0

x = $40 to make....sells for $120 so profit is $80

y = $30 to make...sells for $90 so profit is $60

80x + 60y ≥ 2400

AlekseyPX4 years ago
5 0

Each bicycle gives a profit of around 60 dollars.

2400/60= 40

The store must sell around 40 bicycles every month.

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\begin{gathered} \frac{1.6}{(1+r)^8}=a \\ \Rightarrow2.3=\frac{1.6}{(1+r)^8}(1+r)^{16} \\ \Rightarrow2.3=1.6(1+r)^8 \\ \Rightarrow\frac{2.3}{1.6}=(1+r)^8 \\ \Rightarrow(\frac{2.3}{1.6})^{\frac{1}{8}}=(1+r)^{}^{} \\ \Rightarrow r=(\frac{2.3}{1.6})^{\frac{1}{8}}-1 \\ \Rightarrow r=0.0464078 \end{gathered}

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a) Thus, the equation is

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\begin{gathered} f(36)=1.113043\ldots(1+0.0464078\ldots)^{36} \\ \Rightarrow f(36)=5.6983\ldots \end{gathered}

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