All categories

3 years ago

21) What is the slope of the line that is perpendicular to the line of the given equation y = 5x

1 answer:

5 0

To find the perpendicular slope, take the slope you have, change it’s sign, and flip it upside down.

5 -> -5 (change its sign)
-5 -> -1/5 (flip it upside down)

Perpendicular slope is -1/5.

Remember a whole number can be treated as that whole number over 1.
5 = 5/1
That allows you to flip it.

You might be interested in

To approximate the number of bees in a hive, multiply the number of bees that leave the hive in one minute by 3 and divide by 0.

AlekseyPX

Answer:

There are about 5,357 bees in the hive

Step-by-step explanation:

Let

x -----> the number of bees that leave the hive in one minute

y -----> the approximate number of bees in a hive

we know that

The formula to calculate the approximate number of bees in a hive is equal to

$y=\frac{3x}{0.014}$

For x=25

substitute

$y=\frac{3(25)}{0.014}$

$y=5,357\ bees$

therefore

There are about 5,357 bees in the hive

6 0

4 years ago

Read 2 more answers

Pls Help - Calc. HW dy/dx problem

GREYUIT [131]

Answer:

$\displaystyle y' = \frac{-2}{x \ln (10)[\log (x) - 2]^2}$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Addition/Subtraction]: $\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]$

Derivative Rule [Basic Power Rule]:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]: $\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

Identify.

$\displaystyle y = \frac{\log (x)}{\log (x) - 2}$

Step 2: Differentiate

[Function] Derivative Rule [Quotient Rule]: $\displaystyle y' = \frac{[\log (x) - 2][\log (x)]' - [\log (x) - 2]'[\log (x)]}{[\log (x) - 2]^2}$
Rewrite [Derivative Rule - Addition/Subtraction]: $\displaystyle y' = \frac{[\log (x) - 2][\log (x)]' - [\log (x)' - 2'][\log (x)]}{[\log (x) - 2]^2}$
Logarithmic Differentiation: $\displaystyle y' = \frac{[\log (x) - 2]\frac{1}{\ln (10)x} - [\frac{1}{\ln (10)x} - 2'][\log (x)]}{[\log (x) - 2]^2}$
Derivative Rule [Basic Power Rule]: $\displaystyle y' = \frac{[\log (x) - 2]\frac{1}{\ln (10)x} - \frac{1}{\ln (10)x}[\log (x)]}{[\log (x) - 2]^2}$
Simplify: $\displaystyle y' = \frac{\frac{\log (x) - 2}{\ln (10)x} - \frac{\log (x)}{\ln (10)x}}{[\log (x) - 2]^2}$
Simplify: $\displaystyle y' = \frac{\frac{-2}{\ln (10)x}}{[\log (x) - 2]^2}$
Rewrite: $\displaystyle y' = \frac{-2}{x \ln (10)[\log (x) - 2]^2}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

8 0

2 years ago

What is the area of the prism

babymother [125]

Answer: 72

Step-by-step explanation:

Prism area = b * h

base = 4 * 3 = 12

height = 6

12 * 6 = 72

8 0

3 years ago

Read 2 more answers

Please help. Question a and b

Anit [1.1K]

X roughly equals 3.99

8 0

3 years ago

Could someone help me with this trigonometry question where you have to calculate the length of bc, to the nearest degree.

katrin2010 [14]

Answer: The length of BC ≈ 12.4 cm

Step-by-step explanation:

The first thing we need to do is to find the length of BD which we can solve for with the tangent of 20° which is the opposite side over the adjacent side.

We get tan20° = BD/8.

Solve for BD and you get BD = 8tan20°.

Now we will need to solve for the length of CD which we can get from the tangent of 40°.

We get tan40° = 8/CD

Solve for CD and you get CD = 8/tan40°.

Now that we have the lengths of BD and DC, we can simply add them together to get the length of BC.

(8tan20°) + (8/tan40°) ≈ 12.4 cm

7 0

4 years ago