Question

Divide..................

Answer 1

Answer:

option-A

Step-by-step explanation:

we are given

Dividend is

$6x^2-19x+10$

Divisor is

$2x-5$

we can use long division method

we get

Remainder is

=0

Quotient is

$3x-2$

so, we can write as

$\frac{6x^2-19x+10}{2x-5}=3x-2+\frac{0}{2x-5}$

$\frac{6x^2-19x+10}{2x-5}=3x-2$