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1 year ago

7

Please help me! Im so confused. If you could explain, too that would be great!!! <3

1 answer:

Zielflug [23.3K]1 year ago

8 0

Answer:

the base length is 8 units

Step-by-step explanation:

You can use pythagorean theorem to solve this

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Carbón has an atomic number of 6 what can you conclude about carbon from this fact

Mars2501 [29]

If it is the most common isotope and of Carbon and it is not an ion, you can conclude that it has 6 protons and 6 electrons.

5 0

2 years ago

Distance between A (2, -1) and (2,a) is 4 units. Find the value of a where a is positive.

kolezko [41]

Answer:

a = 3

Step-by-step explanation:

Calculate the distance d using the distance formula and equate to 4

d = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$

with (x₁, y₁ ) = (2, - 1) and (x₂, y₂ ) = (2, a)

d = $\sqrt{(2-2)^2+(a+1)^2}$ = $\sqrt{0+(a+1)^2}$ = $\sqrt{(a+1)^2}$ = a + 1 then

a + 1 = 4 ( subtract 1 from both sides )

a = 3

3 0

2 years ago

What is the exponential regression equation that fits these data? y x 1 4 2 8 3 27 4 85 5 250 6 600

Volgvan

Answer:

its is C because the other ones are obvious wrong. So it has to be C plus i did this test.

Step-by-step explanation:

5 0

2 years ago

For the function y=3x2: (a) Find the average rate of change of y with respect to x over the interval [3,6]. (b) Find the instant

nirvana33 [79]

Answer:

The instantaneous rate of change of $y$ with respect to $x$ at the value $x = 3$ is 18.

Step-by-step explanation:

a) Geometrically speaking, the average rate of change of $y$ with respect to $x$ over the interval by definition of secant line:

$r = \frac{y(b) -y(a)}{b-a}$ (1)

Where:

$a$ , $b$ - Lower and upper bounds of the interval.

$y(a)$ , $y(b)$ - Function exaluated at lower and upper bounds of the interval.

If we know that $y = 3\cdot x^{2}$ , $a = 3$ and $b = 6$ , then the average rate of change of $y$ with respect to $x$ over the interval is:

$r = \frac{3\cdot (6)^{2}-3\cdot (3)^{2}}{6-3}$

$r = 27$

The average rate of change of $y$ with respect to $x$ over the interval $[3,6]$ is 27.

b) The instantaneous rate of change can be determined by the following definition:

$y' = \lim_{h \to 0}\frac{y(x+h)-y(x)}{h}$ (2)

Where:

$h$ - Change rate.

$y(x)$ , $y(x+h)$ - Function evaluated at $x$ and $x+h$ .

If we know that $x = 3$ and $y = 3\cdot x^{2}$ , then the instantaneous rate of change of $y$ with respect to $x$ is:

$y' = \lim_{h \to 0} \frac{3\cdot (x+h)^{2}-3\cdot x^{2}}{h}$

$y' = 3\cdot \lim_{h \to 0} \frac{(x+h)^{2}-x^{2}}{h}$

$y' = 3\cdot \lim_{h \to 0} \frac{2\cdot h\cdot x +h^{2}}{h}$

$y' = 6\cdot \lim_{h \to 0} x +3\cdot \lim_{h \to 0} h$

$y' = 6\cdot x$

$y' = 6\cdot (3)$

$y' = 18$

The instantaneous rate of change of $y$ with respect to $x$ at the value $x = 3$ is 18.

5 0

2 years ago

Mrs. Barrera learned that 21 of

otez555 [7]

Answer:

just do 21/25

Step-by-step explanation:

8 0

2 years ago