Question

Write the expression as a square of a binomial: 0.01x^4+y^2–0.2x^2y ^=square

Answer 1

   

$0.01x^4+y^2-0.2x^2y=\\\\= 0.01x^4-0.2x^2y+y^2 =\\\\=\Big(0.1x^2\Big)^2-2\cdot0.1x^2\cdot y+\Big(y\Big)^2=\\\\=\boxed{\bf \Big(0.1x^2-y\Big)^2}$

Answer 2

That would be

(0.1x^2 - y)^2

Check:-

If we  expand this  (0.1x^2 - y)(0.1x^2 - y)

it =   0,01x^4 - 0.1x^2y - 0.1x^2y + y^2

= 0.01x^4  + y^2 - 0.2x^2y