Assume the population has a distribution with a mean of 110 and a standard deviation of 8. For a random sample of size 40, find
1 answer:
Answer:
109.33
Step-by-step explanation:
given that the population has a distribution with a mean of 110 and a standard deviation of 8
Sample size n = 40
Std error of sample mean = std dev/square root of sample size
=
From std normal distribution table we find that 30th percentile for Z is
-0.5244
Corresponding x score =
30th percentile = 109.33663
=109.33
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Answer: C
<u>Step-by-step explanation:</u>
∑ 8()⁽ⁿ⁻¹⁾ from n = 1 to n = 5
n = 1 → 8()⁽¹⁻¹⁾
= 8 =
n = 2 → 8()⁽²⁻¹⁾
= =
n = 3 → 8()⁽³⁻¹⁾
= =
n = 4 → 8()⁽⁴⁻¹⁾
= =
n = 5 → 8()⁽⁵⁻¹⁾
= =
Sum =
= 408.99