Answer:
Proof below.
Step-by-step explanation:
<u>Quadratic Formula</u>

<u>Given quadratic equation</u>:

<u>Define the variables</u>:
<u>Substitute</u> the defined variables into the quadratic formula and <u>solve for x</u>:







Therefore, the exact solutions to the given <u>quadratic equation</u> are:

Learn more about the quadratic formula here:
brainly.com/question/28105589
brainly.com/question/27953354
Calculate the circumference of the two semi circles, which equals a full circle. Then add the two sides of the track.
Circumference is pi x diameter = 3.14 x 22.8 = 71.592, so, you would need to add 71.592 + 49.2 + 49.2 = 169.992 meters, and that would be the length of one lap of the track.
The answer is B. The data is similar throughout the line.
It's hard to type and hard to read the "inverse tangent" function, as you've seen (above).
So, use "arctan x" instead.
Then the problem becomes: "differentiate cos (arctan x)."
You must apply first the rule for differentiating the cosine function, and next apply the rule for differentiating the arctan function:
(d/dx) cos (arctan x) = - sin (arctan x) * [1/(1+x^2)]
To find the slope intercept form of a line perpendicular to a given equation, the first thing you need to do is to find the slope of the perpendicular line. Because lines perpendicular to one another are always have a slope that is the negative reciprocal of them, the slope of the line perpendicular to y=x would be -1 (since the slope of y=x is 1). Then, since the perpendicular line passes through the point (5, -3), you would plug in the values of the x and y into the equation
y=-1x+b to get -3=-1(5)+b.
When you simplify, solve for b to get b=2. Now that you have your slope (m=-1) and your y-intercept (b=2), you can conclude that your perpendicular equation would be y=-x+2.