Assume the population has a distribution with a mean of 110 and a standard deviation of 8. For a random sample of size 40, find
the 30th percentile of (round off to first decimal place).
1 answer:
Answer:
109.33
Step-by-step explanation:
given that the population has a distribution with a mean of 110 and a standard deviation of 8
Sample size n = 40
Std error of sample mean = std dev/square root of sample size
= 
From std normal distribution table we find that 30th percentile for Z is
-0.5244
Corresponding x score =
30th percentile = 109.33663
=109.33
You might be interested in
-1d-7 is the answer I'm pretty sure
Answer:
b 60 -4x 50 +2x=2,800 is 50 +. 2x
Answer:
I think the answer would be 22.15 but I'm not really sure.
0.73+0.68+0.88+0.74+0.81=3.84
3.84 divided by 5
=0.768x100
=76.8% or 77%
Answer:
Step-by-step explanation:
it is C