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KengaRu [80]
3 years ago
12

Assume the population has a distribution with a mean of 110 and a standard deviation of 8. For a random sample of size 40, find

the 30th percentile of (round off to first decimal place).
Mathematics
1 answer:
VARVARA [1.3K]3 years ago
8 0

Answer:

109.33

Step-by-step explanation:

given that the population has a distribution with a mean of 110 and a standard deviation of 8

Sample size n = 40

Std error of sample mean = std dev/square root of sample size

= \frac{8}{\sqrt{40} } \\=1.265

From std normal distribution table we find that 30th percentile for Z is

-0.5244

Corresponding x score =110-0.5244*1.265=109.33663

30th percentile = 109.33663

=109.33

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