9514 1404 393
Answer:
Step-by-step explanation:
Let a and s represent the prices of adult and student tickets, respectively.
13a +12s = 211 . . . . . . ticket sales the first day
5a +3s = 65 . . . . . . . ticket sales the second day
Subtracting the first equation from 4 times the second gives ...
4(5a +3s) -(13a +12s) = 4(65) -(211)
7a = 49 . . . . . . . simplify
a = 7 . . . . . . . divide by 7
5(7) +3s = 65 . . . . substitute into the second equation
3s = 30 . . . . . . . subtract 35
s = 10 . . . . . . . divide by 3
The price of one adult ticket is $7; the price of one student ticket is $10.
Since 4 nights cost $356, 356÷4=89, so one night costs $89. 7-4=3, so 89×3 is 267. 267+356 is 623. The total cost for 7 nights would be $623
Answer:
7/55 or 12.727272727273%
Step-by-step explanation:
7/55 or 12.727272727273%
7 big and pink
so 7/?
?= amount of bows
and them up and you get 55
7/55
Answer:
14
Step-by-step explanation:
