A quadratic equation has the general formula
expressed as:<span>
ax^2 + bx - c = 0
This equation can be solved by the quadratic
formula which is expressed as:
x = ( -b (+ or -) √(b^2 - 4ac) / 2a
From the given equation, </span><span> y=-0.005x^2+0.41x-5.1
</span><span>
a = -0.005
b = 0.41
c = -5.1
Using the quadratic formula and the corresponding values of the coefficient, we substitute these and obtain:
</span>x = ( -b (+ or -) √(b^2 - 4ac) / 2a
x = ( -0.41 (+ or -) √(0.41^2 - 4(-0.005)(5.1)) / 2(-0.005)
x1 =66.71
x2 = 15.29
Therefore, the quadratic equation would be factored by using the values of x we obtained as follows:
<span>y= -0.005x^2 + 0.41x - 5.1
</span>y = (x - 66.71) ( x - 15.29 )
Answer:
C. 11.60 ounces to 12.60 ounces
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
Approximately 68% of the measures are within 1 standard deviation of the mean.
Approximately 95% of the measures are within 2 standard deviations of the mean.
Approximately 99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean 12.10, standard deviation 0.25.
In which range will the amount of water dispensed be found 95% of the time?
By the Empirical Rule, within 2 standard deviations of the mean. So
12.10 - 2*0.25 = 12.10 - 0.5 = 11.60
12.10 + 2*0.25 = 12.10 + 0.5 = 12.6
So the correct answer is given by option C.
Answer:
A
Step-by-step explanation:
The Explication 0 (7+4i)+(7-4i) = 14
Answer:
5(x-3)(x+2)=0
Step-by-step explanation:
5x^2-30x=5
5x^2-30x-5=0
5(x^2-6x-1)=0
5(x-3)(x+2)=0
Let's first define the variables:
x = width
300 - 2x = long
The area will be:
A = (x) * (300 - 2x)
A = 300x - 2x²
We look for the maximum area, for this, we derive:
A '= 300 - 4x
We match zero:
0 = 300 - 4x
x = 300/4 = 75
Therefore, the width is:
x = 75 feet
The length is:
300 - 2x = 300 - 2 (75) = 300-150
150 feet
Answer:
Part A:
The maximum area will be:
A = (150) * (75) = 11250 square feet
Part B:
The dimensions are:
Length = 150 feet
width = 75 feet
