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Sedbober [7]
3 years ago
8

If the edges of a cube are doubled in length to produce a new, larger cube, then the

Mathematics
1 answer:
vova2212 [387]3 years ago
3 0

take x as the side of the cube.

surface area = 6a^2

= 6x^2

take 2x as the next cube

surface area = 6(2x)^2

= 6 x 4 x x^2

= 24x^2

cube two is 4 times more than cube 1 in surface area wise.

HOPW THIS HELPS AND PLEASE MARK ME AS BRAINLIEST.

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A^-1/[a^-1 - b^-1] + a^-1/[a^-1 + b^-1]
o-na [289]

\dfrac{a^{-1}}{a^{-1}-b^{-1}}+\dfrac{a^{-1}}{a^{-1}+b^{-1}}=a^{-1}\left(\dfrac{a^{-1}+b^{-1}}{(a^{-1}-b^{-1})(a^{-1}+b^{-1})}+\dfrac{a^{-1}-b^{-1}}{(a^{-1}+b^{-1})(a^{-1}-b^{-1})}\right)

=a^{-1}\left(\dfrac{(a^{-1}+b^{-1})+(a^{-1}-b^{-1})}{a^{-2}-b^{-2}}\right)

=\dfrac{2a^{-2}}{a^{-2}-b^{-2}}

=\dfrac{2b^2}{b^2-a^2}

5 0
3 years ago
Read 2 more answers
A plumber charges $90 per hour and a $50 travel fee.
Fittoniya [83]
Okay so subtract 50 from both sides and you would get 360=90x and then divide each side by 90 and you would get x= 4 so it took 4 hours
8 0
3 years ago
Read 2 more answers
The Copy Shop has made 20 copies of a document for you. Since the defective rate is 0.1, you think there may be some defective c
Pepsi [2]

Answer:

Binomial

There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.

Step-by-step explanation:

For each copy of the document, there are only two possible outcomes. Either it is defective, or it is not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem

Of the 20 copies, 2 are defective, so p = \frac{2}{20} = 0.1.

What is the probability that you will encounter neither of the defective copies among the 10 you examine?

This is P(X = 0) when n = 10.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.1)^{0}.(0.9)^{10} = 0.3487

There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.

8 0
3 years ago
Need Help asap<br> Choices<br> 9<br> 18<br> 60<br> 120
Bad White [126]

120 is the right answer that is what my teacher told me

8 0
2 years ago
Multiply (2x+3) (-x -2)
Marysya12 [62]

Answer:

-2x^{2} -7x-6

Step-by-step explanation:

(2x + 3) (-x - 2)

distribute first term, to the second term:

2x(-x) + 2x(-2) + 3(-x) + 3(-2)

multiply:

(-2x^{2}) + (-4x) + (-3x) + (-6)

-2x^{2} -4x-3x-6

combine the like terms:

-2x^{2} - 4x - 3x - 6

             -7x

-2x^{2} - 7x - 6

final answer :

-2x^{2} - 7x - 6

hope this helped !!

mark me brainliest :D

6 0
2 years ago
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