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4 years ago

Which of the table represents a function ?

Mathematics

1 answer:

Gnoma [55]4 years ago

7 0

Function is a process that associates to each element of a set X a one element of a set Y.

Your answer is B.

A-not (double 3);

C-not (double 1);

D - not (double 4)

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Help me ASAP... PLISSSSS

Marina CMI [18]

Answer:

1010 base 9 Changing from base to decimal we start from left side digit and multiply by base

1000 * 9^3 = 729

1 * 9 = 9

We sum and get 738

85 base 9 =

8 * 9 = 72

5 = 5

We sum 72 + 5 = 77 decimal

738 - 77 = 661 decimal

and if the answer must be in base 9 then:

661 decimal = 814 base 9

Step-by-step explanation:

7 0

3 years ago

Evaluate m + n2 if we know m = 2 and n = –2. A. 6 B. –8 C. 8 D. –6

zhuklara [117]

M + n²
= (2) + (-2)²
= 2 + 4
= 6
answer is A. 6
because negative times negative = positive

4 0

3 years ago

Read 2 more answers

In a circuit, two resistors of 100 Ω and 80 Ω are connected in parallel. The parallel group is then connected in series with a 1

nordsb [41]

Answer:

Total Resistance = $\frac{1300}{9}$ Ω (or 144.44 Ω)

Step-by-step explanation:

If two resistors, with resistance x and y, are connected in parallel, their total resistance is given by the formula:

$\frac{1}{Total}=\frac{1}{x}+\frac{1}{y}$

If 2 resistors with resistance x and y and connected in series, their total resistance would be:

Total = x + y

Now, the first part, 100 and 80 are in parallel, so according to formula it would be:

$\frac{1}{Total}=\frac{1}{x}+\frac{1}{y}\\\frac{1}{Total}=\frac{1}{100}+\frac{1}{80}\\\frac{1}{Total}=\frac{9}{400}\\Total = \frac{400}{9}$

Now, this is connected in series with 100, so the grand total would be:

Total Resistance of Circuit = $\frac{400}{9}+100=\frac{1300}{9}$

This is the total resistance of the circuit.

4 0

3 years ago

Question: Simplify the following Inequality: r − 12/−9 > −2 A. r -30

Monica [59]

Answer:

Step-by-step explanation:

r-30

5 0

3 years ago

Can someone explain the answer to 7.1x10^-3 ?

Andrej [43]

Answer:

${ \tt{7.1 \times {10}^{ - 3} }} \\ { \bf{negative \: means \: { \green{increase \: in \: decimal \: places}}}} \\ = { \tt{0.71 \times {10}^{ - 2} }} \\ = { \tt{0.071 \times {10}^{ - 1} }} \\ = { \tt{0.0071 \times {10}^{0} }} \\ { \boxed{ but \: {10}^{0} = 1}} \\ \therefore{ \tt{ = 0.0071 \times 1 = 0.0071}}$

3 0

3 years ago