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Svet_ta [14]
3 years ago
8

1 Point

Mathematics
2 answers:
GrogVix [38]3 years ago
7 0
<h2>Answer:</h2>

The correct graph of the solution to the given compound inequality is:

                                C

<h2>Step-by-step explanation:</h2>
  • The first inequality is given by:

   5x-1

on adding 1 on both the side of the inequality we have:

5x

on dividing both side of the inequality by 5 we have:

x

The graph of this inequality is the shaded region to the left of 4 with a open circle at 4( since the inequality is strict)

  • The second inequality is:

        -3-x+1\leq 1\\\\-3+1-x\leq 1\\\\-2-x\leq 1\\\\-2-1\leq x\\\\x\geq -3

The graph of this inequality is the shaded region to the right of -3 and closed circle at -3 ( since the inequality is not strict i.e. a inequality with a equality sign )

Hence, the graph of the compound inequality is the set of all the points between -3 and 4 including -3 and excluding 4.

alexandr1967 [171]3 years ago
4 0

Answer:

Option C

Step-by-step explanation:

The given inequality is

5x-1 < 19 and -3-x+1\le1

Group similar terms to get:

5x < 19+1 and -x\le1-1+3

5x < 20 and -x\le3

Solve for x to get:

x < 4 and  x\ge -3

The correct choice is C

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Answer:

The answer is 108 I remember it because 9×12 is 108 and that's kinda what it is really.

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Use the change of Base formula to evaluate log5 92 . then convert. Log5 92 to a logarithm in base 3. Round to the nearest thousa
vovikov84 [41]
Change of base is
log_a(b)= \frac{log_c(b)}{log_c(a)}
change base to 3
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anyway, the value would be 2.809555
4 0
3 years ago
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The graph represents this system of equations. What is the solution to the system of equations? a(–2, 4) b( 3, 4) c (4, –2) d(4,
alekssr [168]
Okay. All we have to do is look at this graph and see what points out of those answer choices show up. (-2, 4) is on the line (actually where the line intersects) but what about the others? (4, -2) and (4, 3) are not connected with any of the lines, so C and D are eliminated. (3, 4) is on the line, but that's not where both lines intersect. Intersecting lines at a point shows that the point is the solution, in this case (-2, 4) is the solution to this system of equation. The answer is A: (-2, 4).
6 0
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HELP PICS INCLUDED! WILL GIVE BRAINLIEST! SHOW WORK AND EXPLAIN
Naddik [55]

I assume you know about the dot product, and that for two vectors \mathbf a and \mathbf b, the angle between them \theta satisfies

\mathbf a\cdot\mathbf b=\|\mathbf a\|\|\mathbf b\|\cos\theta\iff\cos\theta=\dfrac{\mathbf a\cdot\mathbf b}{\|\mathbf a\|\|\mathbf b\|}

Then the vectors are parallel if the angle between them is 0 or 180 degrees (0 or pi radians), which would make \cos\theta=1 or \cos\theta=-1, respectively.

Part A)

\vec v_1=\langle\sqrt3,1\rangle\implies\|\vec v_1\|=\sqrt{(\sqrt3)^2+1^2}=\sqrt4=2

\vec v_2=\langle-\sqrt3,-1\rangle=-\vec v_1\implies\|\vec v_2\|=\|\vec v_1\|=2

\vec v_1\cdot\vec v_2=(\sqrt3)(-\sqrt3)+(1)(-1)=-4

Then the angle between \vec v_1,\vec v_2 is such that

\cos\theta=\dfrac{-4}{(2)(2)}=-1\implies\theta=\pi\,\mathrm{rad}

so these vectors are parallel ("antiparallel", more specifically, which means they are parallel but point in opposite directions).

Part B) involves the same computations:

\vec u_1=\langle2,3\rangle\implies\|\vec u_1\|=\sqrt{2^2+3^2}=\sqrt{13}

\vec u_2 has the same components but differing by sign and order, as \vec u_1; its magnitude remains the same, though:

\vec u_2=\langle-3,-2\rangle\implies\|\vec u_2\|=\sqrt{(-3)^2+(-2)^2}=\sqrt{13}

\vec u_1\cdot\vec u_2=(2)(-3)+(3)(-2)=-12

\implies\cos\theta=\dfrac{-12}{(\sqrt{13})(\sqrt{13})}=-\dfrac{12}{13}\implies\theta=\cos^{-1}\left(-\dfrac{12}{13}\right)

which is neither 0 nor pi, which means these vectors are not parallel.

4 0
4 years ago
Please answer and answer
JulijaS [17]

Answer:

Is the C

Step-by-step explanation:

6 0
3 years ago
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