A university offers 3 calculus classes: Math 2A, 2B and 2C. In both parts, you are given data about a group of students who have
1 answer:
Answer:
4 students
Step-by-step explanation:
The total number of students is given by:
Where N is the total number of students, A is the number of students that have taken Math 2A, B is the number of students that have taken Math 2B, and C is the number of students that have taken Math 2C:
4 students in Group A have taken all three classes.
*The number of students that have taken two classes has be subtracted so those students do not get counted twice
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Answer:
a. .92
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
The margin of error of the interval is:
The lower bound is the point estimate subtracted by the margin of error.
The upper bound is the point estimate added to the margin of error.
Point estimate:
The confidence interval is symmetric, so it is the mean between the two bounds.
In this problem:
Sample of 400, which means that
Margin of error is the estimate subtracted by the lower bound. So
We have to find z.
has a pvalue of 0.96.
This means that:
Confidence level:
So the correct answer is:
a. .92
Answer:
0.1978
Step-by-step explanation:
According to the rule of BODMAS (or FEDMAS), let us do the bracket first.
26·11 = 286
Now, do the multiplication from the left.
12·121·3 = 4356
286·7 = 2002
Now, do the division from the left.
= 0.1978