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3 years ago

What are the x and y intercepts of 4x-5y=100?

Mathematics

1 answer:

boyakko [2]3 years ago

7 0

X intercept= (25,0)
y intercept= (0,-20)

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In an area of the Great Plains, records were kept on the relationship between the rainfall (in inches) and the yield of wheat (b

vovikov84 [41]

Answer: D. 0.981

Step-by-step explanation:

Step 1: For the given data table on x^2

We square all values given to us

Step 2: we repeat Same for Y^2 table too.

Step 3: XY table we multiply x and y

Step 4: we make a summation of them all

Step 5: we input our summer value into our formula.

Step 6 : we arrive at our answer which is 0.981

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3 years ago

3x+2y=0 <br> x-5y=17<br><br> Solving system using elimination

horsena [70]

(2,-3) is the answer

6 0

3 years ago

X²+Y²=250 and XY=117<br> What are the values of X and Y?

yan [13]

Answer:

Step-by-step explanation:

$x^2+y^2=250\\\\x^2-2xy+y^2+2xy=250\\\\(x-y)^2=250-2xy\\\\(x-y)^2=250-2\cdot117\\\\ (x-y)^2=16\\\\x-y=4\qquad\qquad\vee\qquad \qquad x-y=-4\\\\x=4+y \qquad\qquad \vee\qquad\qquad x=-4+y\\\\(y+4)y=117\qquad\vee\qquad\quad (y-4)y=117\\\\y^2+4y-117=0\qquad\vee\qquad y^2-4y-117=0\\\\y=\dfrac{-4\pm\sqrt{4^2-4(-117)}}{2\cdot1}\qquad\vee\qquad y=\dfrac{4\pm\sqrt{4^2-4(-117)}}{2\cdot1}\\\\y=\dfrac{-4\pm\sqrt{16+468}}{2}\qquad\ \ \vee\qquad y=\dfrac{4\pm\sqrt{16+468}}{2}$

$y_1=\dfrac{-4-22}{2}\ ,\quad y_2=\dfrac{-4+22}{2}\ ,\quad y_3=\dfrac{4-22}{2}\ ,\quad y_4=\dfrac{4+22}{2}\\\\y_1=-13\ ,\qquad y_2=9\ ,\qquad\quad\qquad\ y_3=-9\ ,\qquad y_4=13\\\\x_{1,2}=4+y_{1,2}\qquad\qquad\qquad\qquad\qquad x_{3,4}=-4+y_{3,4}\\\\x_1=-9\ ,\qquad x_2=13\ ,\qquad\quad\qquad x_3=-13\ ,\qquad x_4=9$

6 0

4 years ago

Please help, I will give brainliest, I am struggling badly.

Alja [10]

Answer:

Step-by-step explanation:

Notice they both have the same slope of 3x so they are parallel, but different y intercepts. This means the lines never intersect and thus there are no solutions to the system of equations.

3 0

3 years ago

Read 2 more answers

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Andrews [41]

Https://photomath.net/s/rRVj6K

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3 years ago