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Ugo [173]
3 years ago
15

WILL GIVE 20 POINTS

Mathematics
1 answer:
Oksanka [162]3 years ago
3 0

Answer:

The answer is B

Step-by-step explanation:

75 + x = 90

First, Virginia had to write an equation to solve for x.

75 - 75 + x = 90 - 75

Second, Virginia used the subtraction property of equality to isolate x.

x = 15

Third, "x = 15" was the answer Virginia got after subtracting 90 and 75.

75 + 15 = 90

Finally, she had to verify her answer

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If a triangle has a height of 14 inches and a base of 9 inches what's the area
enot [183]

area = 1/2 x h x b

14*9 = 126

126/2 = 63 square inches

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3 years ago
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What is the best estimate of 11 1/5÷2 3/4
likoan [24]

Answer:4

Step-by-step explanation:

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3 years ago
Use the graph that shows the solution to
Luda [366]

Answer:

The solution for f(x) = g(x) are;

x = 1 and x = -1

Step-by-step explanation:

The given equations for the functions, g(x) are;

f(x) = \dfrac{1 + 2\cdot x}{x}

g(x) = 2 + x

The solution for f(x) = g(x), is given by equating the equations of the two functions as follows;

When f(x) = g(x), we have;

\dfrac{1 + 2\cdot x}{x} = 2 + x

By cross multiplication, we have;

1 + 2·x = x × (2 + x) = 2·x + x²

∴ x² + 2·x - 2·x - 1 = 0

x² - 1 = 0

(x - 1)·(x + 1) = 0

x = 1, or x = -1

f(x) = g(x) = 2 + 1 = 3, or 2 - 1 = 1

Therefore, the solution for f(x) = g(x) are;

f(x) = g(x) = 3 or 1 where x = 1 and x = -1.

6 0
2 years ago
Surface area of a box dimensions of 16 18 and 14
Arada [10]
16×14×2+16×18×2+14×18×2=1528
3 0
3 years ago
The circumference of a sphere was measured to be 80 cm with a possible error of 0.5 cm. A) Use differentials to estimate the max
siniylev [52]

Answer:

A) The maximum error in the calculated surface area: 25cm^2

Relative error: 0.013

B) The maximum error in the calculated volume: 162cm^2

Relative error: 0.019

Step-by-step explanation:

A) The formula for the surface area is:

A=4\pi r^2

The measured value is the circumference which is equal to:

C=2\pi r

then the radius is:

r=\frac{C}{2\pi}

Substituting in the formula of the surface:

A=4\pi(\frac{C}{2\pi})^2\\A=4\pi(\frac{C^2}{4\pi^2})\\A=\frac{C^2}{\pi}

Using the formula to calculate the error:

dy=f'(x)dx

Where x is the variable measured and y is a function of x(y=f(x)).

dA=f'(C)dC\\dA=\frac{2C^{(2-1)}}{\pi}dC\\dA=\frac{2C}{\pi}dC

We have C=80cm and dC=0.5cm

dA=\frac{2C}{\pi}dC\\dA=\frac{2(80)}{\pi}(0.5)\\dA=\frac{160}{\pi}(0.5)\\dA=50.9296(0.5)\\dA=25.4648\approx25cm^2

The relative error is the maximum error divide by the total area. The total area is: A=\frac{C^2}{\pi}=\frac{(80)^2}{\pi}=\frac{6400}{\pi}=2037.1833cm^2

\frac{dA}{A}=\frac{25.4648}{2037.1833} =0.0125\approx0.013

B) The formula for the volume is:

V=\frac{4}{3} \pi r^3

Using r=\frac{C}{2\pi}

V=\frac{4}{3} \pi r^3\\V=\frac{4}{3} \pi (\frac{C}{2\pi})^3\\V=\frac{4}{3} \pi (\frac{C^3}{8\pi^3})\\V=\frac{1}{3}(\frac{C^3}{2\pi^2})\\V=\frac{C^3}{6\pi^2}

The maximum error is:

dV=\frac{3C^{3-1}}{6\pi^2}dC\\dV=\frac{C^{2}}{2\pi^2}dC\\dV=\frac{(80)^{2}}{2\pi^2}(0.5)\\dV=\frac{6400}{2\pi^2}(0.5)\\dV=\frac{6400}{2\pi^2}(0.5)\\dV=(324.2278)(0.5)\\dV=162.1139\approx162cm^2

The calculated volume is:

V=\frac{C^3}{6\pi^2}\\V=\frac{(80)^3}{6\pi^2}\\V=\frac{512000}{6\pi^2}\\V=8646.0743

The relative error is:

\frac{dV}{V}=\frac{162.1139}{8646.0743}=0.0188\approx0.019

3 0
3 years ago
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