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Evgesh-ka [11]
3 years ago
7

Veda solves the following system of linear equations by elimination. What is the value of x in the solution of the system

Mathematics
1 answer:
densk [106]3 years ago
6 0

Answer:

work shown and pictured

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Consider ΔABC, where ∠C = 90° and ∠A + ∠B = 90°. Click on the statements that are true about the relationships of the angles Ang
Novay_Z [31]

Answer: Angles A and B are complementary angles

If Sin A ≈ 0.766 then Cos B ≈ 0.766.

If Cos B ≈ 0.766 then Sin A ≈ 0.766

Step-by-step explanation: In any given right angled triangle, one angle measures 90 degrees while the addition of the other two angles equals to 90 degrees. Hence if angle C is given as 90 degrees, then angles A and B added together equals 90 degrees (complementary angles equal 90 degrees).

Also, Sin A cannot be the same value as Sin B, since angle A and angle B are not equal in measurement. However, being complementary, the Sin of angle A equals the Cos of angle B.

If Sin A ≈ 0.766, then angle A ≈ 50 degrees

That makes angle B equal to 40 degrees. The Cos of B ≈ 0.766

Therefore if Sin A ≈ 0.766, then Cos B ≈ 0.766

If Cos B ≈ 0.766 then Sin A ≈ 0.766 are both correct

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3 years ago
8x + 16 = 8<br> What is x
Fofino [41]
The answer to that equation is X= -1
6 0
3 years ago
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ASAP Someone please help me! PLEASE, I BEG My grade is going down and i can only count on u guys!
kirza4 [7]
Additive inverses combine to get 0. So, k is -1.4. The sum is 0. Hopefully that will help.
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3 years ago
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If f (n)(0) = (n + 1)! for n = 0, 1, 2, , find the taylor series at a=0 for f.
Pie
Given that f^{(n)}(0)=(n+1)!, we have for f(x) the Taylor series expansion about 0 as

f(x)=\displaystyle\sum_{n=0}^\infty\frac{(n+1)!}{n!}x^n=\sum_{n=0}^\infty(n+1)x^n

Replace n+1 with n, so that the series is equivalent to

f(x)=\displaystyle\sum_{n=1}^\infty nx^{n-1}

and notice that

\displaystyle\frac{\mathrm d}{\mathrm dx}\sum_{n=0}^\infty x^n=\sum_{n=1}^\infty nx^{n-1}

Recall that for |x|, we have

\displaystyle\sum_{n=0}^\infty x^n=\frac1{1-x}

which means

f(x)=\displaystyle\sum_{n=1}^\infty nx^{n-1}=\frac{\mathrm d}{\mathrm dx}\frac1{1-x}
\implies f(x)=\dfrac1{(1-x)^2}
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3 years ago
How many solutions in x^2=64
Hitman42 [59]

Answer:

x = 8

x = -8

Step-by-step explanation:

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