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shutvik [7]
3 years ago
12

When a projector is placed 10 meters from a screen as shown, it produces an image 3 meters high. If the tallest image that the p

rojector can produce without distortion is 4.5 meters high, what is the maximum distance the projector can be placed from the screen? 12 meters
Mathematics
2 answers:
LenKa [72]3 years ago
6 0

Answer:

15 meters

Step-by-step explanation:

rjkz [21]3 years ago
3 0
It can be placed 15 meters from the screen
You might be interested in
(theta) = 168°; t = 0.28 sec; r = 3 mm. find its linear velocity.​
Leokris [45]

Answer:

  • 0.03 m/sec

Step-by-step explanation:

<h3>Given</h3>
  • Θ= 168°
  • t = 0.28 sec
  • r = 3 mm
<h3>To find </h3>
  • Linear velocity
<h3>Solution</h3>

<em>Formula for linear velocity</em>

  • v = Θr/t

<u>Converting the angle measure from degrees to radians</u>

  • 168° = 168*π/180 = 168*3.14/180 = 2.93

<u>Substituting values</u>

  • v = 2.93*3/0.28 mm/sec =
  • 31.39 mm/sec =
  • 0.03 m/sec rounded to nearest hundredths

6 0
4 years ago
. Find the smallest value of k such that 3240k is a perfect cube.
Stels [109]
The product of multiple perfect cubes is also a perfect cube.
Proof for two:
n^3 * p^3 = nnnppp = npnpnp = (np)^3
And any integer whose exponent is a multiple of 3 is a perfect cube.
We will use this here:

Prime factorize 3240:
3240 = 405 * 2^3 = 2^3 * 3^4 * 5^1
We need to multiply this by k, to make all the exponents divisible by 3
The exponents not divisible by 3 are 4 and 1.
So let's fix that:
2^3 * 3^4 * 3*2 * 5^1 * 5^2
So, k is 3^2 * 5^2 = 225
(3240*225)^(1/3) = 90
8 0
3 years ago
Solve 3(x + 2) &gt; X.<br> {xlx&lt;-1}<br> {x1x&gt;-17<br> {x\x&lt;-3)<br> [x\x&gt;-31
Georgia [21]

Answer:

-3 < x

Step-by-step explanation:

3(x + 2) > X.

Distribute

3x+6 >x

Subtract 3x from each side

3x-3x +6 >x-3x

6> -2x

Divide each side by -2, remembering to flip the inequality

6/-2 < -2x/-2

-3 < x

7 0
3 years ago
If y varies directly as x and x = 9 when y = 15 , find y when x = 33
poizon [28]
This would practically be very reliable of course. We can see in the sentence above that y and x, and x and y are both depending on each other. So, now that this has been considered, we can see that whenever "x" would be a certain number, this would show you that "y" would also be a certain number, and depending how much "x" or "y" would move, it would also change these variable no matter how they move.

This would be a matter of division. As we can see above on how 9 and 15 could be divisible down the line as they multiply.

Therefore, we would then see how many times would "x" which is 9, how many times that would go in 33.

Let's start!

\boxed{33\div9= \ (3.6)}

We take this "3.6" away from this, and we would plug it into "y".

We then do the following:

\boxed{3.6*15=55}

Therefore, when "x" = 33, "y" would then equal 55.

Your answer: \boxed{\boxed{\bf{y=55}}}
5 0
3 years ago
Read 2 more answers
which expression is equivalent to (^3sqrtm)^7 in exponential form? a) 7 m/3 b) 3 m/7 c) m 3/7 d) m 7/3
Komok [63]
(\sqrt[3]{m})^{7} = m^{ \frac{7}{3}}
5 0
3 years ago
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