A total of 3.75 x 10⁷ transcription factors are phosphorylated in response to the first messenger. The number of transcription factors phosphorylated if one copy of the d enzyme is inactivated is 3.7499 x 10⁷.
<h3>What is phosphorylation?</h3>
Phosphorylation is a posttranslational modification that suffers proteins during the activation of a singling pathway.
Phosphorylation is capable of activating and/or deactivating specific signaling pathways.
In this case, phosphorylation activates a molecular cascade involving the progressive phosphorylation of different substrates.
In this case, 3.75 x 10⁷ transcription factors are phosphorylated in response to the first messenger (100 x 100 x 75 x 50 = 3.75 x 10⁷), whereas the number of transcription factors phosphorylated if one copy of d enzyme is inactivated is 3.7499 x 10⁷ (3.75 x 10⁷ - 50).
Learn more about phosphorylation here:
brainly.com/question/19578076
The reason for that is they both have the same charge, there for your hair will stand on end. Your hair is simply trying to get as far away from the other charge as it can.
Answer:
legal if ur 18
Explanation:
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The limit from 1 to 2 of the given antiderivative is; -0.19865
<h3>What is the Limit of the Integral?</h3>
We are given the antiderivative of f(x) as sin(1/(x² + 1)). Thus, to find the limit from 1 to 2, we will solve as;
⇒ (sin ¹/₅) - (sin ¹/₂)
⇒ 0.19866 - 0.47942
⇒ -0.19865
Complete Question is;
If sin(1/(x² + 1)) is an anti derivative for f(x), then what is the limit of f(x)dx from 1 to 2?
Read more about integral limits at; brainly.com/question/10268976
Answer: the population has a mean of less than 30
Explanation:
In interval estimation, the t distribution is applicable only when a. the population has a mean of less than 30. the sample standard deviation (s) is given instead of the population standard deviation
