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galben [10]
3 years ago
8

Can some pls help me with these two questions plss

Mathematics
1 answer:
tankabanditka [31]3 years ago
6 0
19. a^2+b^2=c^2
3^2+4^2=c^2
25=c^2
5=c
RS is 5 units

20. 3.14*6^2*10
3.14*36*10=1130.4

volume is 1130.4
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A company was able to increase its staff from 200 employees to 348
nexus9112 [7]

Answer:

The percent increase is 74%

Step-by-step explanation:

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3 years ago
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What is the zero of the function, y = -1/4x + 5 and describe the location of the x-intercept on the coordinate plane.
Anon25 [30]

Answer:

It crosses the y-axis at (0,5)

It crosses the x-axis at (20,0)

4 0
3 years ago
What integer represents w? 9 : 4 = 27 : w
joja [24]

Answer:

12

Step-by-step explanation:

This is because to get 9 to 27 you have to multiply 9 by 3, therefore you have to multiply 4 by 3 due to the fact what you do to one side you have to do to the other to make it all equal:

9 x 3 = 27

4 x 3 = 12

ratio- 9 : 4 = 27 : 12

have a nice night! Hope this helped

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2 years ago
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Find the smallest number by which432 must be multiplied so that their products are a perfect sqaure​
snow_tiger [21]

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i hope this help you

5 0
3 years ago
NO LINKS!! Use the method of substitution to solve the system. (If there's no solution, enter no solution). Part 11z​
Roman55 [17]

Answer:

(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}

(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}

Step-by-step explanation:

Given system of equations:

\begin{cases}y=x^2-9\\y=4x-4\end{cases}

To solve by the method of substitution, substitute the first equation into the second equation and rearrange so that the equation equals zero:

\begin{aligned}x^2-9&=4x-4\\x^2-4x-9&=-4\\x^2-4x-5&=0\end{aligned}

Factor the quadratic:

\begin{aligned}x^2-4x-5&=0\\x^2-5x+x-5&=0\\x(x-5)+1(x-5)&=0\\(x+1)(x-5)&=0\end{aligned}

Apply the <u>zero-product property</u> and solve for x:

\implies x+1=0 \implies x=-1

\implies x-5=0 \implies x=5

Substitute the found values of x into the <u>second equation</u> and solve for y:

\begin{aligned}x=-1 \implies y&=4(-1)-4\\y&=-4-4\\y&=-8\end{aligned}

\begin{aligned}x=5 \implies y&=4(5)-4\\y&=20-4\\y&=16\end{aligned}

Therefore, the solutions are:

(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}

(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}

6 0
1 year ago
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