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Yakvenalex [24]

3 years ago

11

an isosceles triangle has two sides of 18 centimeters. It’s height is 14 centimeters. What is the length of the base of the tria

ngle?

1 answer:

marta [7]3 years ago

6 0

Answer:

252cm

Step-by-step explanation:

18/2=2

9*14=126

126*2=252

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Rita and Tina each make $11 an hour working as cashiers at a supermarket. Last week, Rita worked r hours while Tina worked t hou

Alexxx [7]

Answer:

11(t+r)+35

Step-by-step explanation:

they make 11 dollars an hour so you have to multiply 11 by t hour an r hours. then only one of them worked overtime so you add 35.

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3 years ago

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WITCHER [35]

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Step-by-step explanation:

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7 0

3 years ago

4(px + 1) = 64<br> what is the value of x in terms of p ?

Sedaia [141]

Answer:

x = 15/p

Step-by-step explanation:

4(px + 1) = 64

4px + 4 = 64

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4px/p = 60/p

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4 0

3 years ago

Given that f(x) = x2 + 2x + 3 and g(x) = quantity of x plus four, over three , solve for f(g(x)) when x = 2.

Sidana [21]

$f(x)=x^2+2x+3$
$g(x)=\frac{x+4}{3}$
$f(g(x))=(\frac{x+4}{3})^2+2(\frac{x+4}{3})+3$
$f(g(x))=\frac{x^2+8x+16}{9}+\frac{2x+8}{3}+3$
$f(g(2))=\frac{2^2+8(2)+16}{9}+\frac{2(2)+8}{3}+3$
$f(g(2))+\frac{4+16+16}{9}+\frac{4+8}{3}+3$
$f(g(2))=\frac{36}{9}+\frac{12}{3}+3$
$f(g(2))=4+4+3$
$f(g(2)=11$

Check:
g(2)=(2+4)/3=2
f(2)=2^2+2(2)+3=4+4+3=11 Checks.

4 0

3 years ago

Read 2 more answers

Unknown angle problems (with ale<br> Solve for I in the diagrarn below.<br> (24 + 45)<br> f<br> TE

astraxan [27]

Answer:

x = 45

Step-by-step explanation:

The angles with (2x + 45) and x are supplementary angles, meaning they add up to 180°. We can write this statement as an algebraic equation of $2x + 45 + x = 180$ and solve it.

Step 1: Combine like terms.

$(2x+x)+45=180$
$3x+45=180$

Step 2: Subtract 45 from both sides.

$3x + 45 - 45 = 180 - 45$
$3x = 135$

Step 3: Divide both sides by 3.

$3x/3 = 135/3$
$x = 45$

Step 4: Check if solution is correct.

$2(45) + 45 + 45 = 180$
$90 + 90 = 180$
$180=180$

Therefore, x = 45.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

8 0

2 years ago