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34kurt
4 years ago
12

Martin had 7 pounds of grapes left, and he gave away 2/5 of them. Explain how to use compatible numbers to estimate the amount o

f grapes he gave away.
Mathematics
2 answers:
Dima020 [189]4 years ago
7 0
<span>2/5 is close to 1/2, and it is easy to find 1/2 of 7 mentally. Half of 7 is 3.5, so Martin gave away about 3.5 pounds.</span>
oee [108]4 years ago
4 0

Answer:

Martin gave away about 3.5 pounds.

Step-by-step explanation:

its easy

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Step-by-step explanation:

<u>Given</u><u> </u><u>:</u><u>-</u><u> </u>

<em> </em>

<em>the</em><em> line </em><em>passes </em><em>thr</em><em>ough</em><em> </em><em>the </em><em>point</em><em> ( </em><em>0</em><em> , -</em><em>7</em><em> </em><em>)</em>

<em>)and slope of the line is </em><em>(</em><em> </em><em>-</em><em>2</em><em>/</em><em>3</em><em> </em><em>)</em>

<em>• To form an equation when one point and it's slope is given , </em>

<em>• To form an equation when one point and it's slope is given , we use ;</em>

<em>• To form an equation when one point and it's slope is given , we use ;( y - y1 ) = m ( x - x1 )</em>

<em>• To form an equation when one point and it's slope is given , we use ;( y - y1 ) = m ( x - x1 )Where , x and y are variables</em>

<em>• To form an equation when one point and it's slope is given , we use ;( y - y1 ) = m ( x - x1 )Where , x and y are variablesand x1 and y1 are the points where the line meet ! </em>

<em>• To form an equation when one point and it's slope is given , we use ;( y - y1 ) = m ( x - x1 )Where , x and y are variablesand x1 and y1 are the points where the line meet ! and m is slope of the tangent !!</em>

<em>y1</em><em> </em><em>=</em><em> </em><em>-</em><em>7</em>

<em>x1</em><em> </em><em>=</em><em> </em><em>0</em>

<em>So, putting all the values in the equation we get ,</em>

<em>(y - ( - 7)) =  \frac{( -2 )}{3} (x - 0) \\  \\ y + 7 =  \frac{ - 2}{3} x \\  \\ 3y + 21 =  - 2x \\  \\ 3y =  - 2x - 21</em>

<em>3y =  - 21 - 2x \\  \\ y =   \frac{ - 2}{3} x -  \frac{21}{3  }  \\  \\ y =  \frac{ - 2}{3} x - 7</em>

<em>• Slope intercept form of the equation </em>

<em>• Slope intercept form of the equation y = mx + c </em>

<em>• Slope intercept form of the equation y = mx + c Where , m is slope of the line </em>

<em>• Slope intercept form of the equation y = mx + c Where , m is slope of the line and c is y intercept !! </em>

<em>[</em><em> </em><em>also</em><em> </em><em>,</em><em> </em><em>we</em><em> </em><em>can</em><em> </em><em>direc</em><em>tly</em><em> </em><em>put</em><em> </em><em>the</em><em> </em><em>value</em><em> </em><em>of</em><em> </em><em>c</em><em> </em><em>=</em><em> </em><em>-</em><em>7</em><em> </em><em>and</em><em> </em><em>m</em><em> </em><em>=</em><em> </em><em>(</em><em> </em><em>-</em><em>2</em><em>/</em><em>3</em><em> </em><em>)</em><em> </em><em>from</em><em> </em><em>given</em><em> </em><em>]</em>

<em>Hence , here m = </em><em>(</em><em>-</em><em>2</em><em>/</em><em>3</em><em> </em><em>)</em><em> and c = </em><em>-</em><em>7</em>

<em>So, the required equation is y = </em><em>(</em><em> </em><em>-</em><em>2</em><em>/</em><em>3</em><em> </em><em>)</em><em>x</em><em> </em><em>-</em><em>7</em>

5 0
3 years ago
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