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3 years ago

Any help. (5 marks)

Mathematics

1 answer:

anyanavicka [17]3 years ago

6 0

Population of England in 2003 = 383 * 130,281 = 49,897,623

In 2008 this is 0.84 * 61,000,000 = 51,240,000

Increase = 51,240,000 - 49,897,623 = 1,342,377

Answer is 1,300,000 to 2 significant figures.

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Rebecca is a Texas resident and she plans to attend Texas Tech for all 4 years of college. She has a yearly

LenKa [72]

Answer:

To complete $m dollars that will suffice Rebecca for her college education, she needs $(m - 60,000).

Step-by-step explanation:

Suppose Rebecca needs $m to complete her four-year college education, given that she has a yearly scholarship of $10,000, she would have $10,000 × 4 = $40,000 for the four years she would spend in college.

With her savings of $20,000, she has $20,000 + $40,000 = $60,000 in total.

To complete the required $m dollars for her college, she needs $(m - 60,000).

6 0

3 years ago

When point B (5, -1) is rotated 180º about the origin, its coordinate becomes (-5, 1).

Shtirlitz [24]

When a point (x,y) rotated 180⁰ about origin, the new point will be (-x, -y).

So,

if we have (5, -1), it should become (-5, 1).

So,

answer is true.

7 0

3 years ago

The population of a heard of cattle numbered was 5000 to begin with and was 10,000 after 10 years. If the population was growing

Lapatulllka [165]

Answer:

$r=0.0718$ . The closest value from your given choices is C)r=0.69

Step-by-step explanation:

To solve this we are using the standard exponential growth equation:

$f(t)=A(1+r)^t$

where

$f(t)$ is the final population after $t$ years

$A$ is the initial population

$r$ is the growth rate in decimal form

$t$ is the time in years

We know from our problem that the initial population is 5000, the final population is 10000, and the time is 10 years, so $A=5000$ , $f(t)=10000$ , and $t=10$ .

Let's replace the values and solve for $r$ :

$f(t)=A(1+r)^t$

$10000=5000(1+r)^{10}$

Divide both sides by 5000

$\frac{10000}{5000} =(1+r)^{10}$

$2=(1+r)^{10}$

Take root of 10 to both sides

$\sqrt[10]{2} =\sqrt[10]{(1+r)^{10}}$

$\sqrt[10]{2} =1+r$

Subtract 1 from both sides

$\sqrt[10]{2}-1=r$

$r=\sqrt[10]{2}-1$

$r=1.0718-1$

$r=0.0718$

We can conclude that the growth rate of our exponential equation is $r=0.0718$ . The closest value from your given choices is C)r=0.69

3 0

4 years ago

What is a counterexample of the statement “all square roots are irrational”

skad [1K]

Rather than trying to guess and check, we can actually construct a counterexample to the statement.

So, what is an irrational number? The prefix "ir" means not, so we can say that an irrational number is something that's not a rational number, right? Since we know a rational number is a ratio between two integers, we can conclude an irrational number is a number that's not a ratio of two integers. So, an easy way to show that not all square roots are irrational would be to square a rational number then take the square root of it. Let's use three halves for our example:

$\sqrt{(\frac{3}{2})^2}=\\\sqrt{\frac{9}{4}}=\\\frac{3}{2}$

So clearly 9/4 is a counterexample to the statement. We can also say something stronger: All squared rational numbers are not irrational number when rooted. How would we prove this? Well, let $\frac{a}{b}$ be a rational number. That would mean, $\frac{a^2}{b^2}$ , would be a/b squared. Taking the square root of it yields:

$\sqrt{\frac{a^2}{b^2}}}=\\ \frac{\sqrt{a^2}}{\sqrt{b^2}}=\\ \frac{a}{b}$

So our stronger statement is proven, and we know that the original claim is decisively false.

3 0

3 years ago

If b=5 and c=3 what is the perimeter of the quadrilateral? Please help

Ymorist [56]

peremeter =l.muttiply by b,so 5.multiply by 3=15

7 0

4 years ago