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3 years ago

Convert 200 degrees to radians

Mathematics

1 answer:

Degger [83]3 years ago

8 0

Answer:

200degrees equal 3.49066 radians

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Somebody please help quick! solve for x

ololo11 [35]

Answer:

x = 8

Step-by-step explanation:

51° = 4x + 19

32° = 4x

8 = x

5 0

3 years ago

Read 2 more answers

1+sin^2 x = 2-cos^2 x

Alinara [238K]

1+sin²x=2-cos²x
Remenber: sin²x+cos²x=1 ⇒sin²x=1-cos²x

1+sin²x=1+(1-cos²x)=2-cos² x (this is true)

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3 years ago

A parallelogram has a length of 15cm and a height of 7.5cm . Calculate it’s area (step by step)

poizon [28]

Answer:

Area of parallelogram is equal to $112.5cm^2$

Step-by-step explanation:

It is given length pf parallelogram which is equal to base of parallelogram is b=15 cm

Height of parallelogram h = 7.5 cm

We have to find the area of the parallelogram.

Area of parallelogram is equal to multiplication of base and height.

Therefore area of parallelogram is,

$A=bh$ , here b is base and h is height.

So $A=15\times 7.5=112.5cm^2$

Therefore area of parallelogram is equal to $112.5cm^2$

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3 years ago

Write the answer to each problem in terms of the variable.

Liono4ka [1.6K]

(34 - R) will be the <span>expression of the other number</span>.

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3 years ago

Find the vector that has the same direction as 3, 2, −6 but has length 2.

Nata [24]

Answer:

The vector is $\vec r = \left(\frac{6}{7},\frac{4}{7},-\frac{12}{7}\right)$ .

Step-by-step explanation:

We can determine the equivalent vector ( $\vec r$ ), dimensionless, by means of the following formula:

$\vec r = \frac{\vec u}{\|\vec u\|} \cdot \|\vec r\|$ (1)

Where:

$\vec u$ - Original vector, dimensionless.

$\|\vec u\|$ - Norm of the original vector, dimensionless.

$\|\vec r\|$ - Norm of the new vector, dimensionless.

The norm of the original vector is determined by the following definition:

$\|\vec u\| = \sqrt{\vec u\,\bullet \,\vec u}$ (2)

If we know that $\vec u = (3, 2, -6)$ , then the norm of the original vector is:

$\|\vec u\| = \sqrt{(3)\cdot (3)+(2)\cdot (2)+(-6)\cdot (-6)}$

$\|\vec u\| = 7$

If we know that $\|\vec r\| = 2$ , then the new vector is:

$\vec r = \frac{2}{7}\cdot (3,2,-6)$

$\vec r = \left(\frac{6}{7},\frac{4}{7},-\frac{12}{7}\right)$

The vector is $\vec r = \left(\frac{6}{7},\frac{4}{7},-\frac{12}{7}\right)$ .

7 0

3 years ago