Cavalieri's principle states that if two solids of equal height have equal cross-sectional areas at every level parallel to the respective bases, then the two solids have equal volume.
Step 1) You would need to convert your 2 fractions into equivalent numbers. In this case, the closet gcf (greatest common factor) is 12. So, 5/4 would convert to 15/12 and 2/3 converts to 8/12.
Step 2) You know have your decimals that are equivalent. All you have left now is to subtract. Take 15/12 and subtract 8/12 from it. You would now get 7/12 of a mile that is still needed to run.
Step 3) Usually, you would simplify your new fraction. In this case, our fraction doesn't simplify. It will stay 7/12 of a mile. For example, If our number had ended up being 4/12, then we would simplify it to 1/3 of a mile. Because, 4 divided by 4 is 1 and 12 divided by 4 is 3. You can't simplify your answer anymore.
Hope this helped!
So, let's begin...
First off, you must note that the question is asking for the d value when you substitute the value of c(x).
You are given the following information:
1. The c(x) value is already given to be 0.75x.
2. The equation to find d of (any value) is 0.8y-5.
So, substitute the value of 0.75x as a y value into 0.8y - 5. This is because you are substituting the value of c(x) for d. This is equal to 0.8 times 0.75x - 5. This is equal to 0.6x - 5, which is the function. Thus, your final answer is d(c(x)) = 0.6x - 5.
If you have any questions please comment. Otherwise, hope this helps! :)
Hello,
When you have an inscribed quadrilateral, the opposite sides are supplementary.
So you can write and solve the following equation.
x + 6x + 19 = 180
7x + 19 = 180
7x = 161
x = 23
Now, plug in 23 for X and we will find the measurement of B.
6(23) + 19
138 + 19
157
The measure of angle B is 157 degrees. (The picture is not drawn to scale)
Good luck,
MrEQ
The answer is B.
For an expression to be a polynomial term, any variables in the expression must have whole number powers.
-3/x isn’t a polynomial term because the variable is in the denominator.
