Let the one type of the bread be bread A
The second type of the bread be bread B
Let the flour be 'f' and the butter be 'b'
We need 150f + 50b for bread A and 75f + 75b for bread B
We can compare the amount of flour and bread needed for each bread and write them as ratio
FLOUR
Bread A : Bread B
150 : 75
2 : 1
We have a total of 2250gr of flour, and this amount is to be divided into the ratio of 2 parts : 1 part. There is a total of 3 parts.
2250 ÷ 3 = 750 gr for one part then multiply back into the ratio to get
Bread A : Bread B = (2×750) : (1×750) = 1500 : 750
BUTTER
Bread A : Bread B = 50 : 75 = 2 : 3
The amount of butter available, 1250 gr is to be divided into 2 parts : 3 parts.
There are 5 parts in total
1250 ÷ 5 = 250 gr for one part, then multiply this back into the ratio
Bread A: Bread B = (2×250) : (3×250) = 500 : 750
Hence, for bread A we need 1500 gr of flour and 500 gr of butter, and for bread B, we need 750 gr of flour and 750 gr of butter.
Answer:
-4/5
Step-by-step explanation:
r=x/2
a=2x
ar²=-1/16
x^3=-1/8
x=-1/2
sn=a/1-r
=-4/5
Answer:
A
Step-by-step explanation:
5/4*4/13=20/182=10/91 you take the red marble out so you -1 from the red and the total bag of marbles then you multiply them to gather to get the combined average then simplify
Remember you can do anything to an equation or inequality as long as ou do it to both sides
also, when multiplying by a negative number in an inequality, don't forget to flip the sign
5+5(x+4)<20
minus 5 from both sides
5(x+4)<15
divide both sides by 5
x+4<3
minus 4 from both sides
x<-1
METHOD 1
f(3) = 20
f(4) = 30
f(5) = 42
f(6) = 56
rate of change
f(4)-f(3)=10
f(5)-f(4)=12
f(6)-f(5)=14
then the average of change is 10+12+14 /3 = 12
METHOD 2 --- faster
rate of change = f(6)-f(3) / 6-3
= (36+18+2)-(9+9+2) / 3
= 36/3 = 12
