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lina2011 [118]
2 years ago
14

The opposite corners of a quadrilateral are right angles. The quadrilateral is not a rhombus. What kind of quadrilateral is this

figure. Explain how you know
Mathematics
1 answer:
tatiyna2 years ago
8 0
A rhombus is a 4 sided shape with equal lengths. Even though it has equal lengths, it has opposite sides that are parallel, and angles that are equal. It also has diaginols (dashed lines) meat in the middle
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What is the area of CDEF? Please could you also say how you got your answers, it will be much appreciated.
ziro4ka [17]
This image has the step by step solution

7 0
3 years ago
charity is four times as old as her daughter. she is also six years younger than her husband. The sum of their ages ten years to
Pachacha [2.7K]

Answer:

36years

Step-by-step explanation:

Let charity present age be x

Charity daughter present age be y

Charity husband present age be z

If the sum of their ages ten years to come is 117, then;

10+x+10+y+10+z = 117

30+x+y+z = 117

x+y+z = 87 ... 1

If charity is four times as old as her daughter, then;

x = 4y

y = x/4 ... 2

If she is also six years younger than her husband, then;

x = z- 6

z = x+6 .. 3

Substitute 2 and 3 into 1;

x + x/4 + (x+6) = 87

Multiply through by 4

4x + x + 4(x+6) = 4(87)

5x+4x+24 = 348

9x = 348 - 24

9x = 324

x = 324/9

x = 36

hence Charity is 36years old today

5 0
2 years ago
This year the CDC reported that 30% of adults received their flu shot. Of those adults who received their flu shot,
Vlad [161]

Using conditional probability, it is found that there is a 0.1165 = 11.65% probability that a person with the flu is a person who received a flu shot.

Conditional Probability

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

In this problem:

  • Event A: Person has the flu.
  • Event B: Person got the flu shot.

The percentages associated with getting the flu are:

  • 20% of 30%(got the shot).
  • 65% of 70%(did not get the shot).

Hence:

P(A) = 0.2(0.3) + 0.65(0.7) = 0.515

The probability of both having the flu and getting the shot is:

P(A \cap B) = 0.2(0.3) = 0.06

Hence, the conditional probability is:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.06}{0.515} = 0.1165

0.1165 = 11.65% probability that a person with the flu is a person who received a flu shot.

To learn more about conditional probability, you can take a look at brainly.com/question/14398287

7 0
2 years ago
(\tan ^(2)\theta \cos ^(2)\theta -1)/(1+\cos (2\theta ))=
Vitek1552 [10]

(tan²(<em>θ</em>) cos²(<em>θ</em>) - 1) / (1 + cos(2<em>θ</em>))

Recall that

tan(<em>θ</em>) = sin(<em>θ</em>) / cos(<em>θ</em>)

so cos²(<em>θ</em>) cancels with the cos²(<em>θ</em>) in the tan²(<em>θ</em>) term:

(sin²(<em>θ</em>) - 1) / (1 + cos(2<em>θ</em>))

Recall the double angle identity for cosine,

cos(2<em>θ</em>) = 2 cos²(<em>θ</em>) - 1

so the 1 in the denominator also vanishes:

(sin²(<em>θ</em>) - 1) / (2 cos²(<em>θ</em>))

Recall the Pythagorean identity,

cos²(<em>θ</em>) + sin²(<em>θ</em>) = 1

which means

sin²(<em>θ</em>) - 1 = -cos²(<em>θ</em>):

-cos²(<em>θ</em>) / (2 cos²(<em>θ</em>))

Cancel the cos²(<em>θ</em>) terms to end up with

(tan²(<em>θ</em>) cos²(<em>θ</em>) - 1) / (1 + cos(2<em>θ</em>)) = -1/2

7 0
2 years ago
Of the 20 plants in Melissa's
vagabundo [1.1K]

Answer:

35 % are herbs

Step-by-step explanation:

7    = 35

20  = 100

6 0
3 years ago
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