4 years ago

Helpppp

Mathematics

1 answer:

OLga [1]4 years ago

3 0

I think the answer is C.

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3 years ago

It is given that m=3x+1 and y= (5/1+m^2).<br>Find dy/dx in terms of x.<br>

DiKsa [7]

Answer:

${ \underline{ \bf{ \frac{dy}{dx} = - \frac{30m}{ {(1 + {m}^{2}) }^{2} } }}}$

Step-by-step explanation:

${ \bf{m = 3x + 1}} \\ { \sf{ \frac{dm}{dx} = 3 }} \\ \\ { \bf{y = \frac{5}{1 + {m}^{2} } }} \\ \\ { \tt{ \frac{dy}{dm} = \frac{ - 10m}{ {(1 + {m}^{2} )}^{2} } }}$

Using chain rule:

${ \boxed{ \bf{ \frac{dy}{dx} = \frac{dy}{dm}. \frac{dm}{dx} }}}$

${ \sf{ \frac{dy}{dx} = - \frac{10m}{ {(1 + {m}^{2}) }^{2} } \times 3}} \\ \\ { \sf{ \frac{dy}{dx} = - \frac{30m}{ {(1 + {m}^{2}) }^{2} } }}$

${ \underline{ \sf{ \blue{christ \:† \: alone }}}}$

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3 years ago

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