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Vlad [161]
3 years ago
8

(look at the image) can i get help on this?

Mathematics
1 answer:
irinina [24]3 years ago
3 0
Yeah you prob can tbh
You might be interested in
Please answer asap will give the highest points possible
natali 33 [55]
Let cheese wafers = x
chocolate wafers = y

we know they bought 20 total packets so x+y = 20, this can be re-written as x = 20-y

cheese wafers cost 2, so we have 2x
chocolate wafers cost 1, so we have 1y, which is just the letter y

so we know 2x + y = $25

replace x with x=20-y to get:

2(20-y)+y = 25

distribute the parenthesis:

40-2y +y = 25

combine like to terms to get:
40-y = 25

subtract 40 from each side"
-y = -15

divide both sides by -1
y = 15

chocolate wafers was y so they bought 15 chocolate wafers
cheese wafers was x, so they bought 20-15 = 5 cheese wafers
 
using the substitution method was the easiest way to isolate one of the variables in order to find the solution.



6 0
3 years ago
Read 2 more answers
6. Evaluate 7C4.<br> 840<br> 210<br> 6<br> 35
AleksAgata [21]

Answer:

210

Step-by-step explanation:

8 0
3 years ago
What are the exact values of sin(2π3radians) and cos(2π3radians)
deff fn [24]
We know that
2π/3 radians-------> convert to degrees-----> 2*180/3---> 120°
120°=90°+30°

Part a) Find <span>sin(2π/3)
</span>sin(2π/3)=sin (90°+30°)
we know that
sin (A+B)=sin A*cos B+cos A*sin B
so
sin (90°+30°)=sin 90*cos 30+cos 90*sin 30
sin 90=1
cos 30=√3/2
cos 90=0
sin 30=1/2
sin (90°+30°)=1*√3/2+0*1/2-----> √3/2

the answer part a) is
sin(2π/3)=√3/2

Part b) Find cos (2π/3)
cos (2π/3)=cos (90°+30°)
we know that
cos (A+B)=cos A*cos B-sin A*sin B
so
cos (90°+30°)=cos 90*cos 30-sin 90*sin 30
sin 90=1
cos 30=√3/2
cos 90=0
sin 30=1/2
cos (90°+30°)=0*√3/2-1*1/2----> -1/2

the answer part b) is
cos (2π/3)=-1/2
8 0
3 years ago
I need assistance solving these questions using Cramers' Rule (which I am frankly terrible at) and need these to finish my homew
Scrat [10]

Answer:

What are the questions?

3 0
3 years ago
Read 2 more answers
the first term of an arithmetic sequence is 10 and the sum of the first five terms is 250,find the sequence​
Crazy boy [7]

Answer:

The  sequence  is:

10, 30, 50, 70, 90.....................

Step-by-step explanation:

We have,

First term (a) = 10

Common difference (d) = ?

Sum of first 5 terms (S_{5}) = 250

or, \frac{n}{2} [{2a+(n-1)d}] = 250

or, \frac{5}{2} [2*10 + 4d]=250

or, \frac{5}{2} * 4[5+d]=250

or, 10(5 + d) =250

or, 5 + d = 25

∴ d = 20

Now,

2nd term = a + d = 10 + 20 = 30

3rd term = a + 2d = 10 + 2*20 = 10 + 40 = 50

4th term = a + 3d = 10 + 3*20 = 10 + 60 = 70

5th term = a + 4d = 10 + 4*20 = 10 + 80 = 90

8 0
3 years ago
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