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SIZIF [17.4K]
3 years ago
7

What is the slope of the line that passes through the points

Mathematics
2 answers:
Whitepunk [10]3 years ago
8 0

Answer:

-5/2

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-29-(-9))/(15-7)

m=(-29+9)/8

m=-20/8

simplify

m=-5/2

Anuta_ua [19.1K]3 years ago
6 0

Answer:

-5/2

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-29-(-9))/(15-7)

m=(-29+9)/8

m=-20/8

simplify

m=-5/2

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Please answer today or tomorrow. The outside temperature was 5 degrees Fahrenheit. How many degrees below the freezing point of
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water freezes in 32 degrees

so 32-5=27

so it was 27 degrees bellow the freezjng point of water

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Help timed test! At which root does the graph...
Anastaziya [24]

Answer:

x = -2

Step-by-step explanation:

The way you can tell if the graph is going to cross the x-axis or just touch the x-axis is by looking at the power of the factor.

(x - 5)^3 has a power of 3 which is an ODD number. An ODD power means that the graph will cross through the x-axis.

(x + 2)^2 has a power of 2 which is an EVEN number. An EVEN power means that the graph will touch the x-axis.

To find where it will touch the axis set the factor equal to zero and solve.

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subtract 2 from both sides

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3 years ago
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4 0
3 years ago
A coin is flipped 10 times where each flip comes up either heads or tails. How many possible outcomes (a) contain exactly two he
Tems11 [23]

Answer:

a. 45

b. 176

c. 252

Step-by-step explanation:

First take into account the concept of combination and permutation:

In the permutation the order is important and it is signed as follows:

P (n, r) = n! / (n - r)!

In the combination the order is NOT important and is signed as follows:

C (n, r) = n! / r! (n - r)!

Now, to start with part a, which corresponds to a combination because the order here is not important. Thus

 n = 10

r = 2

C (10, 2) = 10! / 2! * (10-2)! = 10! / (2! * 8!) = 45

There are 45 possible scenarios.

Part b, would also be a combination, defined as follows

n = 10

r <= 3

Therefore, several cases must be made:

C (10, 0) = 10! / 0! * (10-0)! = 10! / (0! * 10!) = 1

C (10, 1) = 10! / 1! * (10-1)! = 10! / (1! * 9!) = 10

C (10, 2) = 10! / 2! * (10-2)! = 10! / (2! * 8!) = 45

C (10, 3) = 10! / 3! * (10-3)! = 10! / (2! * 7!) = 120

The sum of all these scenarios would give us the number of possible total scenarios:

1 + 10 + 45 + 120 = 176 possible total scenarios.

part c, also corresponds to a combination, and to be equal it must be divided by two since the coin is thrown 10 times, it would be 10/2 = 5, that is our r = 5

Knowing this, the combination formula is applied:

C (10, 5) = 10! / 5! * (10-5)! = 10! / (2! * 5!) = 252

252 possible scenarios to be the same amount of heads and tails.

6 0
3 years ago
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