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balandron [24]
3 years ago
9

How many tens are there in 432.

Mathematics
2 answers:
Ludmilka [50]3 years ago
6 0
There is about 43 tens in 432.

I hope this helped!!!:)
svp [43]3 years ago
5 0
Th answer would be 43 :)
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PLEASE HELP <br> the answer is not <br> 1/4^-2
hram777 [196]

Answer:

4^3÷4^5

4^(3-5)

4^-2

1/4^2

6 0
3 years ago
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What is the area and permater of a squre whose side is 3x plus 5
deff fn [24]
Area= height x length
        = (3x+5)²
        = 9x²+30x+25

Perimeter= All sides added together
                = 4 (3x+5)
                = 12x + 20

Hope this helps!
3 0
4 years ago
Help me!!!<br> im stuck here<br> if you could help me answer this then please do!!!1
kondaur [170]

Answer:

123.4

Step-by-step explanation:

So I added all of the numbers then divide by how many numbers there was so I divided by 5 because I also counted the x as part of it.

3 0
3 years ago
Simplify 10 to the 6 power over 10 to the negative 3
dimulka [17.4K]
To simplify 10^6/10^-3 you first need to get rid of the negative exponents so you bring up 10^-3 so it becomes:
10^6x10^3 then all that you have to do is add the exponents since the bases for both are the same.
So the final answer is:
10^9
Or in other words:
10 to the power of 9
7 0
3 years ago
Suppose that in a certain population, individuals’ heights are approximately nor-mally distributed with parametersμ=70 andσ=3 in
ruslelena [56]

Answer:

a) 25.14% of the population is over 6ft tall.

b) Both are going to be normally distributed.

Centimeters: \mu = 177.8, \sigma = 7.62cm

Meters: \mu = 1.778, \sigma = 0.0762cm

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Normally distributed with parameters \mu = 70, \sigma = 3.

a.What proportion of the population is over 6 ft. tall?

We have to convert from ft to inches.

Each feet has 12 inches, so 6ft = 72in.

This proportion is 1 subtracted by the pvalue of Z when X = 72. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{72 - 70}{3}

Z = 0.67

Z = 0.67 has a pvalue of 0.7486.

This means that 1-0.7486 = 0.2514 = 25.14% of the population is over 6ft tall.

b.What is the distribution of heights if they are expressed in centimeters? Inmeters?

It is going to still be normally distributed. We just have to convert the mean and the standard deviation from inches to centimeters and meters.

In centimeters.

Each inch has 2.54cm. So it is going to be normally distributed with \mu = 70*2.54 = 177.8cm and \sigma = 3*2.54 = 7.62xm

In meters

Each m has 100cm. So

\mu = 1.778m, \sigma = 0.0762m.

7 0
4 years ago
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