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Leto [7]
3 years ago
9

Which expression is equivalent to ?

Mathematics
1 answer:
mamaluj [8]3 years ago
5 0

Answer:

Step-by-step explanation:

\frac{(a^{2}b^{4}c)^{2}*(6a^{3}b)*(2c^{5})^{3}}{4a^{6}b^{12}c{^3}}\\\\=\frac{a^{2*2}b^{4*2}c^{2}6a^{3}b2^{3}c^{5*3}}{4a^{6}b^{12}c{^3}}\\\\=\frac{a^{4}b^{8}c^{2}6a^{3}b8c^{15}}{4a^{6}b^{12}c{^3}}\\\\=\frac{6*8*a^{4+3}b^{8+1}c^{2+15}}{4a^{6}b^{12}c{^3}}\\\\=\frac{6*2*a^{7}b^{9}c^{17}}{a^{6}b^{12}c{^3}}\\\\=\frac{12a^{7-6}c{17-3}}{b^{12-9}}\\\\=\frac{12a^{1}c^{14}}{b^{3}}\\\\=\frac{12ac^{14}}{b^{3}}

Hint:

x^{m}*x^{n}=x^{m+n}\\\frac{x^{m}}{x^{n}}=x^{m-n},m>n\\\frac{x^{m}}{x^{n}}=\frac{1}{x^{n-m}},n>m

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valentina_108 [34]

Answer:

Q1:  p = - 33

Q2: d = - 99

Q3: t = - 13

Step-by-step explanation:

Q1: $ \textbf{-} \frac{\textbf{p}}{\textbf{3}} \hspace{1mm}  \textbf{-} \hspace{1mm}  \textbf{8} \hspace{1mm}  \textbf{=} \hspace{1mm} \textbf{3}

We solve this taking LCM.

We get: $ \frac{-p - 24}{3} = 3 $

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$ \implies \textbf{p} \hspace{1mm}  \textbf{=} \hspace{1mm}  \textbf{- 33} $

Q4: $ \frac{\textbf{d}}{\textbf{11}} \hspace{1mm}  \textbf{-} \hspace{1mm}  \textbf{4} \hspace{1mm}  \textbf{=} \hspace{1mm}  \textbf{- 13} $

Again we proceed like Q1 by taking LCM.

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$ \implies d = - 143 + 44 $

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We club the like terms on either side.

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Answer:

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Step-by-step explanation:

Use each of the domain values in the function to see what the corresponding range value is.

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The range is the set of numbers {-1, 5, 8}.

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<em>Additional comment</em>

The values in a set are generally listed lowest to highest. The coefficient of x in the equation for f(x) is negative, meaning the lowest range value will correspond to the highest domain value. If you start by finding f(2) = -1, you immediately eliminate all answer choices except B and C.

Those choices differ only in the middle value, so you can tell which is correct by evaluating f(x) for the middle domain value: f(0) = 5. Only one answer choice has both -1 and 5 in the set.

(There are two answers here: how you work the problem, and how you game a multiple choice question.)

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