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lutik1710 [3]
3 years ago
6

Help PLEEEASE QUICK​

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
4 0
I think the one you chose is correct
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A is the correct answer

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SpyIntel [72]

|\Omega|=C(16,2)=\dfrac{16!}{2!14!}=\dfrac{15\cdot16}{2}=120\\|A|=C(6,2)+C(10,2)=\dfrac{6!}{2!4!}+\dfrac{10!}{2!8!}=\dfrac{5\cdot6}{2}+\dfrac{9\cdot10}{2}=15+45=60\\\\P(A)=\dfrac{60}{120}=\dfrac{1}{2}=50\%

3 0
4 years ago
Read 2 more answers
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