We are given two binomials: x+4 , x^2-9.
x+4 can't be factored. Therefore, it is a prime.
Let us work on x^2-9.
9 could be written as 3^2.
Therefore, x^2-9 = x^2 - 3^2.
Now, we can apply difference of the squares formula to factor it.
We know a^2 -b^2 = (a-b) (a+b).
Therefore, x^2 - 3^2 can be factored as (x-3) (x+3).
So, x^2-9 is not a prime binomial because it can be factored as (x-3) (x+3).
Answer:
-21n + 16
Step-by-step explanation:
Start with distributive property
-24n + 16 + 3n
Combine like terms
-21n + 16
There is a part of the equation missing so I can't solve completely
Answer:
1 31/36 is your answer
Step-by-step explanation:
Find common denominators. Note that what you do to the denominator, you must do to the numerator;
(-7/18)(2/2) = (-14/36)
(-9/4)(9/9) = (-81/36)
Combine the terms:
(-14/36) - (-81/36)
Note that two negative signs directly next to each other equals a positive sign.
(-14/36) + 81/36
-14/36 + 81/36
(-14 + 81)/36
Combine like terms. Solve the parenthesis:
(67)/36
Change to a mixed fraction:
(67/36) = 1 31/36
1 31/36 is your answer.
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