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3 years ago

Write (b^2)^3 without exponents

Mathematics

2 answers:

g100num [7]3 years ago

7 0

Answer:

b*b*b*b*b*b

Step-by-step explanation:

(b^2)^3=b^6 since exponents raised to the exponent is just multiplying the two.

b^6 since you cant have exponents is b*b*b*b*b*b or b multiplied by itslef 6 times

Contact [7]3 years ago

3 0

Answer:

b(b)(b)(b)(b)(b)

Step-by-step explanation:

((b²))³ is b⁶ since exponents raised to the exponent is just multiplying the two or 2(3)=6

b⁶ since you can not have exponents is b(b)(b)(b)(b)(b) or b multiplied by itself 6 times so

b(b)(b)(b)(b)(b)

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3 years ago

- 7(2-1) = 28 The solution is?

Aneli [31]

Answer:

Is there a x somewhere or is that litteraly how the equation is?

If so, -7 multiplied by 2 is -14,

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add it together and you get

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4 years ago

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dezoksy [38]

Answer:

let's see what to do buddy...

Step-by-step explanation:

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Multiply the sides of the equation by 799

$zinc = \frac{3}{17} \times 799 \\ \\ zinc = \frac{3}{17} \times 17 \times 47 \\ \\ zinc = 3 \times 47 = 141$

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And we're done.

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3 years ago

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Dennis_Churaev [7]

Answer:

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3 years ago

Read 2 more answers