Answer:
She should use the example of "the wave" in stadiums to illustrate the idea of a nerve impulse.
Explanation:
"The wave" in a sport stadium is a good example to explain how a nerve impulse works because it shows how an action potential travels from one point to its destination making changes in the membrane potential that would be the equivalent of people standing up and sitting down to allow the next row to do the same to reach its final destination.
Answer:
I think it's B They contain many of the sensory cells found within the skin.
Explanation:
Please mark me brainliest if correct
Activation energy ........
A) This is predator-prey relationship.
B) Species A is prey and species B is predator.
- If prey population decreases in number, the predator population will also decrease because there is not enough food for predators to survive and vice versa.
- If predator population decreases, the prey population will increase because less prey will be eaten by predators and vice versa.
C) Let population A be Zebras, and population B Lions.
From the graph, at the beginning the there is increase in Lions, as well as in smaller rate in Zebras. At one point, the population of Lions begins to decrease, so they will eat less Zebras. This will allow Zebras to increase population. With more Zebras on the menu, more Lions will eat and increase their chance to survive. This leads to decrease in Zebra population. But again, with less Zebras, the Lion population must decrease allowing Zebra population to increase, and so on.
Answer:
1/8
Explanation:
Given that the trihybrid parents have AaBbCc genotype for fruit color. The trait is a quantitative trait i.e. each dominant allele will have an additive effect on it. In this case, AaBbCc and AABBCC will not produce same fruit color because AaBbCc has only three loci contributing to the color while in AABBCC all the six loci are contributing to the color. For an offspring to be exactly similar to the AaBbCc parents it should have the same genotype of AaBbCc.
The probability of Aa to come from a cross between Aa and Aa is 2/4 or 1/2
The probability of Bb to come from a cross between Bb and Bb is 2/4 or 1/2
The probability of Cc to come from a cross between Cc and Cc is 2/4 or 1/2
So the collective probability of AaBbCc offspring from a cross between AaBbCc and AaBbCc parents would be=
1/2 * 1/2 * 1/2 = 1/8
Hence, assuming no effects of the environment, 1/8 of the offspring will have the same fruit color phenotype as the trihybrid parent.
