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3 years ago

Find the value of x. round the length to the nearest tenth

Mathematics

2 answers:

Olenka [21]3 years ago

6 0

Answer:

777.9 meters

Step-by-step explanation:

From the given figure the angle adjacent to 40 degree is 50 degree

because it forms a right angle triangle (90 degree)

Now we use trigonometric ratio to find out the hypotenuse x

cos = adjacent side / hypotenuse

$cos(50)= \frac{adjacent}{hypotenuse}$

$cos(50)= \frac{500}{x}$

Cross multiply it

$x= \frac{500}{cos(500)}$

x=777.8619

So x= 777.9 meters

Ronch [10]3 years ago

3 0

Answer:

777.9 meters

Step-by-step explanation:

Notice that the angles of the right triangle are 40 and 50 degrees, with the 500 meter side adjacent to the 50 degree angle. Now, we can set up an equation: cos (50 degrees) = 500 / x. Use a calculator to find that the answer is 777.9.

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The sales tax on a $25,000 car is $1375. What is the sales tax rate?

Slav-nsk [51]

Answer:

$11 sales tax per $200

Step-by-step explanation:

1375/25,000 = 11/200

8 0

3 years ago

Read 2 more answers

A magazine provided results from a poll of 500500 adults who were asked to identify their favorite pie. Among the 500500 respon

Komok [63]

Answer:

99% confidence interval is wider as compared to the 80% confidence interval.

Step-by-step explanation:

We are given that a magazine provided results from a poll of 500 adults who were asked to identify their favorite pie.

Among the 500 respondents, 14% chose chocolate pie, and the margin of error was given as plus or minus ±3 percentage points.

The pivotal quantity for the confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of adults who chose chocolate pie = 14%

n = sample of adults = 500

p = true proportion

Now, the 99% confidence interval for p = $\hat p \pm Z_(_\frac{\alpha}{2}_) \times \sqrt{\frac{\hat p(1-\hat p)}{n} }$

Here, $\alpha$ = 1% so $(\frac{\alpha}{2})$ = 0.5%. So, the critical value of z at 0.5% significance level is 2.5758.

Also, Margin of error = $Z_(_\frac{\alpha}{2}_) \times \sqrt{\frac{\hat p(1-\hat p)}{n} }$ = 0.03 for 99% interval.

So, 99% confidence interval for p = $0.14 \pm2.5758 \times \sqrt{\frac{0.14(1-0.14)}{500} }$

= [0.14 - 0.03 , 0.14 + 0.03]

= [0.11 , 0.17]

Similarly, 80% confidence interval for p = $0.14 \pm 1.2816 \times \sqrt{\frac{0.14(1-0.14)}{500} }$

Here, $\alpha$ = 20% so $(\frac{\alpha}{2})$ = 10%. So, the critical value of z at 10% significance level is 1.2816.

Also, Margin of error = $Z_(_\frac{\alpha}{2}_) \times \sqrt{\frac{\hat p(1-\hat p)}{n} }$ = 0.02 for 80% interval.

So, 80% confidence interval for p = [0.14 - 0.02 , 0.14 + 0.02]

= [0.12 , 0.16]

Now, as we can clearly see that 99% confidence interval is wider as compared to 80% confidence interval. This is because more the confidence level wider is the confidence interval and we are more confident about true population parameter.

5 0

3 years ago

Please help me on this

serious [3.7K]

Just rotate it 90 degrees clockwise like this