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3 years ago

Question 1 Determine the midpoint of the segment with endpoint (-9,3) and (7,-8). Question 2

Mathematics

2 answers:

PilotLPTM [1.2K]3 years ago

8 0

Answer:

m (-1, -2.5)

Step-by-step explanation:

x1=-9 x2=7 y1= 3 y2=-8

-9+ 7 3+ -8

m= ------------ , -----------

2 2

m= -2/2, -5/2

m (-1, -2.5)

mario62 [17]3 years ago

6 0

Answer:

(-1, -2.5)

Step-by-step explanation:

the midpoint of a segment is $(\frac{x1+x2}{2} ,\frac{y1+y2}{2}$ $)$ , given points (x1, y1) and (x2, y2)

$midpoint=(\frac{-9+7}{2}, \frac{3-8}{2} )$ $= (\frac{-2}{2}, \frac{-5}{2} ) = (-1, -2.5)$

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Find the locus of a point such that the sum of its distance from the point ( 0 , 2 ) and ( 0 , -2 ) is 6.

jok3333 [9.3K]

Answer:

$\displaystyle \frac{x^2}{5}+\frac{y^2}{9}=1$

Step-by-step explanation:

We want to find the locus of a point such that the sum of the distance from any point P on the locus to (0, 2) and (0, -2) is 6.

First, we will need the distance formula, given by:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Let the point on the locus be P(x, y).

So, the distance from P to (0, 2) will be:

$\begin{aligned} d_1&=\sqrt{(x-0)^2+(y-2)^2}\\\\ &=\sqrt{x^2+(y-2)^2}\end{aligned}$

And, the distance from P to (0, -2) will be:

$\displaystyle \begin{aligned} d_2&=\sqrt{(x-0)^2+(y-(-2))^2}\\\\ &=\sqrt{x^2+(y+2)^2}\end{aligned}$

So sum of the two distances must be 6. Therefore:

$d_1+d_2=6$

Now, by substitution:

$(\sqrt{x^2+(y-2)^2})+(\sqrt{x^2+(y+2)^2})=6$

Simplify. We can subtract the second term from the left:

$\sqrt{x^2+(y-2)^2}=6-\sqrt{x^2+(y+2)^2}$

Square both sides:

$(x^2+(y-2)^2)=36-12\sqrt{x^2+(y+2)^2}+(x^2+(y+2)^2)$

We can cancel the x² terms and continue squaring:

$y^2-4y+4=36-12\sqrt{x^2+(y+2)^2}+y^2+4y+4$

We can cancel the y² and 4 from both sides. We can also subtract 4y from both sides. This leaves us with:

$-8y=36-12\sqrt{x^2+(y+2)^2}$

We can divide both sides by -4:

$2y=-9+3\sqrt{x^2+(y+2)^2}$

Adding 9 to both sides yields:

$2y+9=3\sqrt{x^2+(y+2)^2}$

And, we will square both sides one final time.

$4y^2+36y+81=9(x^2+(y^2+4y+4))$

Distribute:

$4y^2+36y+81=9x^2+9y^2+36y+36$

The 36y will cancel. So:

$4y^2+81=9x^2+9y^2+36$

Subtracting 4y² and 36 from both sides yields:

$9x^2+5y^2=45$

And dividing both sides by 45 produces:

$\displaystyle \frac{x^2}{5}+\frac{y^2}{9}=1$

Therefore, the equation for the locus of a point such that the sum of its distance to (0, 2) and (0, -2) is 6 is given by a vertical ellipse with a major axis length of 3 and a minor axis length of √5, centered on the origin.

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3 years ago

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Expand (2 + a)9 using Pascal’s triangle.

Natalija [7]

Answer:

Step-by-step explanation:

The Pascal triangle is used to determine the coefficients of the terms when we expand the expression.

1 $(A + B) ^ 0$ = 1

1 1 $(A +B ) ^ 1 = 1A + 1B$

1 2 1 $(A+ B) ^ 2 = 1A^2 + 2 AB + 1B^2$

By extending the triangle, you will get the 9th row, which is your expression, of the coefficients. that is

1 9 36 84 126 126 84 36 9 1

Now, fill in AB in the gaps.

1AB + 9 AB + 36AB + 84AB + 126AB + 126AB +84AB + 36AB + 9AB + 1AB

Next, you need to go from the left to fill out the exponent of A and it will go down from 9 (the exponent of the whole thing) . That is

$1A^9B+9A^8B+36A^7B+84A^6B+126A^5B+126A^4B+84A^3B+36A^2B+9A^1B+1A^0B$

Next will be the exponent of B. this time, you go from the right and do the same with A. You can go from the left also, but go up from 0 to 9 for the exponent of B

$1A^9B^0+9A^8B^1+36A^7B^2+84A^6B^3+126A^5B^4+126A^4B^5+84A^3B^6+36A^2B^7+9A^1B^8+1A^0B^9$

The last step is just to simplify the A^0=1 and B^0 =1 at the first and the last terms.

$A^9+9A^8B^1+36A^7B^2+84A^6B^3+126A^5B^4+126A^4B^5+84A^3B^6+36A^2B^7+9A^1B^8+B^9$

Hope you can learn the method

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3 years ago

Bill has saved $825 from his last 8 paychecks. He saved either $75 or $150 a paycheck. Formulate and solve a system of equations

11Alexandr11 [23.1K]

Answer: 5 times

Step-by-step explanation:

Let the number of times that he saved $75 be x.

Let the number of times that he saved $150 be y.

Therefore, based on the information given in the question, we can form an equation which will be:

x + y = 8 ...... i

75x + 150y = 825 ....... ii

From equation I,

x + y = 8

y = 8 - x....... iiii

Put equation iii into ii and this will be:

75x + 150y = 825

75x + 150(8 - x) = 825

75x + 1200 - 150x = 825

75x - 150x = 825 - 1200

-75x = -375

x = 375/75

x = 5

He saved $75 5times from his paycheck.

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3 years ago

Jar a contains 2 white and 4 red balls, where jar b contains 1 white and 1 red ball. a ball is randomly chosen from jar a and pu

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1:1, or 50% if your using percentages

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