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tigry1 [53]
4 years ago
8

If you have the question 2.545 And you have to multiply it do you go to the right or the left​

Mathematics
1 answer:
lisabon 2012 [21]4 years ago
8 0
Right to left is the way you do it
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274 faculty surveyed regarding their plans for the weekend 126 plan to grade papers 132 plan to attend game 130 plan to do chore
Nimfa-mama [501]

Answer:

Step-by-step explanation:

3 0
3 years ago
What is the product of (3x-9) and 6x↑2-2x+5 Write your answer in standard form.
klio [65]

Answer:

a. 18x^3 -60x^2 + 33x - 45

b. No

Step-by-step explanation:

Given:

(3x-9) and 6x^2-2x+5

=> the production of them is:

(3x-9)(6x^2-2x+5) , we will use distributive law to solve this To do that. we first multiply  6x^2-2x+5 by 3x then by -9. This is done as follows

= 3x (6x^2-2x+5) - 9(6x^2-2x+5)  = (3x * 6x^2-3x * 2x+3x *5) - (9* 6x^2-9* 2x+9* 5)\\\\= (18x^3 -6x^2+ 15x) - (54x^2 - 18x +45)

Then Open both brackets

= 18x^3 -6x^2+ 15x -54x^2 + 18x -45

After that, we group the same terms

= 18x^3 -(6x^2 +54x^2)+ (15x  + 18x) -45

= 18x^3 -60x^2 + 33x - 45

(b) Is the product of (3x-9) and  6x^2-2x+5  equal to the product of (9x-3) and 6x^2-2x+5

No, let find the product of (9x-3) and 6x^2-2x+5 , we will use distributive law to solve this as the above example.

= (9x-3)(6x^2-2x+5)

= 9x (6x^2-2x+5) - 3(6x^2-2x+5)

=(9x * 6x^2 - 9x * 2x + 9x *5) - (3* 6x^2 - 3 * 2x + 3* 5)

= (54x^3  - 18x^2+ 45x) - (18x^2 - 6x +15)

After that, we open the bracket to find the same terms

= 54x^3  - 18x^2+ 45x -18x^2 + 6x -15

= 54x^3  - 18x^2 -18x^2 + 45x  + 6x -15

= 54x^3  - 36x^2 + 51x  -15  

As you can see 54x^3  - 36x^2 + 51x  -15   ≠18x^3 -60x^2 + 33x - 45

Hope it will find you well.

3 0
4 years ago
Please show work to thank you​
Galina-37 [17]

Answer:

Step-by-step explanation:

1) AC⊥BD and BD bisects AC                         1) given

2) AD≅DC                                                        2) linear bisector thm.

3) ∠ADB and ∠CDB are right angles              3) perpendicular bisector thm.

4) ∠ADB ≅ ∠CDB                                             4) all right ∡'s are congruent

5) BD ≅ BD                                                       5) reflexive POV

6) ΔABD ≅ ΔCBD                                             6) SAS

Hope this helps!

btw, I was not able to put the lines on top of some of the letters, so my apologies.

5 0
3 years ago
Find the required annual interest rate, to the
bezimeni [28]

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill&\$1400\\ P=\textit{original amount deposited}\dotfill &\$1100\\ r=rate\to r\%\to \frac{r}{100}\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years\dotfill &7 \end{cases}

1400=1100\left( 1+\frac{r}{12} \right)^{12\cdot 7}\implies \cfrac{1400}{1100}=\left( 1+\frac{r}{12} \right)^{84}\implies \cfrac{14}{11}=\left( 1+\frac{r}{12} \right)^{84} \\\\\\ \sqrt[84]{\cfrac{14}{11}}=1+\cfrac{r}{12}\implies \sqrt[84]{\cfrac{14}{11}}-1=\cfrac{r}{12}\implies 12\left[ \sqrt[84]{\cfrac{14}{11}}-1 \right]=r \\\\\\ 0.0345\approx r\stackrel{\textit{converting to \%}}{0.0345\cdot 100}\implies 3.45\approx r\implies \stackrel{\textit{rounded up}}{3.4\approx r}

8 0
3 years ago
Help me please <br> I don't get this
liraira [26]
Which answers have a negative sign and which answers have no negative signs. Put them in the right box that has a negative or no negative sign.
 
6 0
3 years ago
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