9th grade algebra homework help??
1 answer:
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Answer:
r = 10
Step-by-step explanation:
You want to find r such that ...
-20 = 60/-6 -r
r = 60/-6 +20 . . . . . add 20+r
r = -10 +20 = 10
_____
If you mean h(x) = 60/(x -r), then the answer is different.
-20 = 60/(-6-r)
-6-r = 60/-20 . . . . . multiply by (-6-r)/(-20)
-r = -3 +6 = 3 . . . . . add 6, simplify
r = -3 . . . . . . . . . . . . multiply by -1
Hehehe idk if true...
SIDE LENGTH OF TRIANGLE: 2.14 inches
SIDE LENGTH OF HEXAGON: 6 inches
To solve this problem, we know that the shapes have equal sides as it states “equilateral triangle”. A triangle has 3 sides and a hexagon has 6 sides. We are told the perimeters are the same so you can set their perimeters equal to each other to solve for x. You would get this : 3(1.4x + 2) = 6(0.5x +2)
With basic algebra you would get x= 5
Then you substitute that value into the length sides of the triangle and hexagon. For the triangle you would approx get 2.14 inches and for the hexagon 6 inches
SIDE LENGTH OF HEXAGON: 6 inches
To solve this problem, we know that the shapes have equal sides as it states “equilateral triangle”. A triangle has 3 sides and a hexagon has 6 sides. We are told the perimeters are the same so you can set their perimeters equal to each other to solve for x. You would get this : 3(1.4x + 2) = 6(0.5x +2)
With basic algebra you would get x= 5
Then you substitute that value into the length sides of the triangle and hexagon. For the triangle you would approx get 2.14 inches and for the hexagon 6 inches