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defon
3 years ago
8

Use the graph of each polynomial function to find the factored form of the related polynomial. Assume the polynomial has no cons

tant factor.
What are the zeros of this function? (2 points) _______, _______
What is the factorization of the polynomial? (2 points)

Mathematics
1 answer:
Serjik [45]3 years ago
3 0

Answer:

  • zeros: x = -2; x = +4
  • factorization: y = (x +2)(x -4)

Step-by-step explanation:

The zeros are where the graph crosses the x-axis (y=0). They are x=-2 and x=4.

The factors are the binomials that are zero when x has the value of a zero:

  y = (x +2)(x -4)

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You have two circles, one with radius r and the other with radius R. You wish for the difference in the areas of these two circl
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Answer:

maximum difference of radii =(r-R)=\frac{1}{2\pi ^{2}}

Step-by-step explanation:

We know that area of circle is given by

A=\pi \times (radius)^{2}

For circle with radius 'r' we have

A_{1}=\pi \times (r)^{2}

For circle with radius 'R' we have

A_{2}=\pi \times (R)^{2}

Now according to given condition we have

A_{1}-A_{2}\leq \frac{5}{\pi }

\Rightarrow \pi r^{2}-\pi R^{2}\leq \frac{5}{\pi }\\\\\Rightarrow (r^{2}-R^{2})\leq \frac{5}{\pi ^{2}}\\\\(r+R)(r-R)\leq \frac{5}{\pi ^{2}}\\\\\because (a^{2}-b^{2})=(a+b)(a-b)\\\\(r+R)=10(Given)\\\\\Rightarrow(r-R)\leq \frac{5}{10\pi ^{2}}\\\\\therefore (r-R)\leq\frac{1}{2\pi ^{2}}

Thus maximum difference of radii =(r-R)=\frac{1}{2\pi ^{2}}

6 0
4 years ago
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Hitman42 [59]
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7 0
4 years ago
Which expression has a value of 8, using only four 4s and any of the following: + , – , • , ÷, exponents, and/or parentheses?
nekit [7.7K]
PEMDAS
A. 4*4-4-4=16-4-4=12-4=8 true
B. 4*4*4-4=16*4-4=64-4=60, not 8 false
C. 4*4+4-4=16+0=16, not 8, incorect
D. 4(4+4)-4=4(8)-4=32-4=28, not 8 incorrect


A
4 0
3 years ago
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4 0
3 years ago
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