Answer: 12 students
Step-by-step explanation:
Let X and Y stand for the number of students in each respective class.
We know:
X/Y = 2/5, and
Y = X+24
We want to find the number of students, x, that when transferred from Y to X, will make the classes equal in size. We can express this as:
(Y-x)/(X+x) = 1
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We can rearrange X/Y = 2/5 to:
X = 2Y/5
The use this value of X in the second equation:
Y = X+24
Y =2Y/5+24
5Y = 2Y + 120
3Y = 120
Y = 40
Since Y = X+24
40 = X + 24
X = 16
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Now we want x, the number of students transferring from Class Y to Class X, to be a value such that X = Y:
(Y-x)=(X+x)
(40-x)=(16+x)
24 = 2x
x = 12
12 students must transfer to the more difficult, very early morning, class.
A
x=y^2-9
x+9=y^2
square root both sides
+-sqrt(x+9)
Answer:
1 ft3= 0,028 m3
Step-by-step explanation:
We know that a 1 ft= 0,305 m,
if we cubed the above equation we have the following
1 ft3= (0,305)^3 m3
1 ft3= 0,028 m3
Answer:
<h2>The answer is option C</h2>
Step-by-step explanation:
Using trigonometric identities
That's
Rewrite the expression
That's
Simplify
We have
So we have
3( - 1)
We have the final answer as
<h2>- 3</h2>
Hope this helps you
