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3 years ago

10 pts

Mathematics

2 answers:

Rasek [7]3 years ago

7 0

Answer:

28 MPH

Step-by-step explanation:

Vaselesa [24]3 years ago

4 0

It’s 8 mph because you have to do distance over time so you do 28 divided by 3.5 and you get 8 which is 8mph

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(1+cos2x)/(1-cos2x) = cot^2x

sesenic [268]

We will turn the left side into the right side.

$\dfrac{1 + \cos 2x}{1 - \cos2x} = \cot^2 x$

Use the identity:

$\cos 2x = \cos^2 x - \sin^2 x$

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Now use the identity

$\sin^2 x + \cos^2 x = 1$ solved for sin^2 x and for cos^2 x.

$\dfrac{\cos^2 x + \cos^2 x }{\sin^2 x + \sin^2 x} = \cot^2 x$

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3 years ago

A golfer keeps track of his score for playing nine holes of golf (half a normal golf round). His mean score is 8080 with a sta

solniwko [45]

Answer:

Therefore the mean and standard deviation of his total score if he plays a full 18 holes are 160 and $11\sqrt2$ respectively.

Step-by-step explanation:

Given that,

For the first 9 holes X:

E(X) = 80

SD(X)=13

For the second 9 holes Y:

E(Y) = 80

SD(Y)=13

For the sum W=X+Y, the following properties holds for means , variance and standard deviation :

E(W)=E(X)+E(Y)

and

V(W)=V(X)+V(Y)

⇒SD²(W)=SD²(X)+SD²(Y) [ Variance = (standard deviation)²]

$\Rightarrow SD(W)=\sqrt{SD^2(X)+SD^2(Y)}$

∴E(W)=E(X)+E(Y) = 80 +80=160

and

∴ $SD(W)=\sqrt{SD^2(X)+SD^2(Y)}$

$=\sqrt{11^2+11^2}$

$=\sqrt{2.11^2}$

$=11\sqrt2$

Therefore the mean and standard deviation of his total score if he plays a full 18 holes are 160 and $11\sqrt2$ respectively.

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3 years ago