7. Krista wrote a list of factors and a list
1 answer:
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Step-by-step explanation:
y-2 = - 3(x-3)
y - 2 =-3x +9
y -2 +2 = - 3x +9 +2
y = - 3x +11
To find the the coordinate
When x =0
y = - 3(0) +11
y= 11
When y = 0
0 = - 3x +11
Subtract 11 from both sides
-3x = - 11
x = 11/3
The y intercept is 11 so, one of your points will be at (0, 11) while the other will be at (11/3, 11).
So remember that in a quadratic equation there is a type of quadratic equation of the form ax^2+bx+c=0 so to find what values of a, b, and c you need for the quadratic formula, you need to look at your equation and label a, b, and c. In this equation a=6, b=5 and c=-4. So for the quadratic formula you would use a=6, b=5 and C=-4. I hope this helps!!!!!
