Question

Triangle BCD is similar to triangle ACE. If the triangles are isosceles, what is the length of AB?

Answer 1

$\frac{2.75}{22} = \frac{5}{ac} \\ ac = 5 \div ( \frac{2.75}{22} ) = 40 \\ ab = 40 - 5 = 35$
Correspondind sides, similar triangles