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3 years ago

Solve this problem. What is n? 6n = 24 n=

Mathematics

2 answers:

saveliy_v [14]3 years ago

8 0

Answer:

n = 4

Step-by-step explanation:

6n = 24

The goal here is to get n by itself. Since n is being multiplied by 6, we can divide it by 6 as well. Now the equation looks like this:

$\frac{6n}{6}$ = 24

Remember though, what you do to one side you have to do to the other. So, we'll also divide 24 by 6.

$\frac{6n}{6}$ = $\frac{24}{6}$

The 6's on the left side cancel each other out and we are left with just n.

n = $\frac{24}{6}$

Divide 24 by 6.

n = 4

dalvyx [7]3 years ago

4 0

Answer:

Step-by-step explanation:

Divide 24 by 6, which equals 4

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Step-by-step explanation:

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3 years ago

A group of friends wants to go to the amusement park. They have no more than $310

Marizza181 [45]

Answer: $35x+9\leq 310,\ 8$

Step-by-step explanation:

Given

A group of friends has $310 to spend

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So, the cost of tickets and parking must be less than or equal to $310

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3 years ago

Solve the above que no. 55

aleksandr82 [10.1K]

Answer:

Let $\left(1+\frac{1}{\tan^{2}A} \right)\cdot \left(1+\frac{1}{\cot^{2}A} \right)$ , we proceed to prove the trigonometric expression by trigonometric identity:

1) $\left(1+\frac{1}{\tan^{2}A} \right)\cdot \left(1+\frac{1}{\cot^{2}A} \right)$ Given

2) $\left(1+\frac{\cos^{2}A}{\sin^{2}A} \right)\cdot \left(1+\frac{\sin^{2}A}{\cos^{2}A} \right)$ $\tan A = \frac{1}{\cot A} = \frac{\sin A}{\cos A}$

3) $\left(\frac{\sin^{2}A+\cos^{2}A}{\sin^{2}A} \right)\cdot \left(\frac{\cos^{2}A+\sin^{2}A}{\cos^{2}A} \right)$

4) $\left(\frac{1}{\sin^{2}A} \right)\cdot \left(\frac{1}{\cos^{2}A} \right)$ $\sin^{2}A+\cos^{2}A = 1$

5) $\frac{1}{\sin^{2}A\cdot \cos^{2}A}$

6) $\frac{1}{\sin^{2}A\cdot (1-\sin^{2}A)}$ $\sin^{2}A+\cos^{2}A = 1$

7) $\frac{1}{\sin^{2}A-\sin^{4}A}$ Result

Step-by-step explanation:

Let $\left(1+\frac{1}{\tan^{2}A} \right)\cdot \left(1+\frac{1}{\cot^{2}A} \right)$ , we proceed to prove the trigonometric expression by trigonometric identity:

1) $\left(1+\frac{1}{\tan^{2}A} \right)\cdot \left(1+\frac{1}{\cot^{2}A} \right)$ Given

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3) $\left(\frac{\sin^{2}A+\cos^{2}A}{\sin^{2}A} \right)\cdot \left(\frac{\cos^{2}A+\sin^{2}A}{\cos^{2}A} \right)$

4) $\left(\frac{1}{\sin^{2}A} \right)\cdot \left(\frac{1}{\cos^{2}A} \right)$ $\sin^{2}A+\cos^{2}A = 1$

5) $\frac{1}{\sin^{2}A\cdot \cos^{2}A}$

6) $\frac{1}{\sin^{2}A\cdot (1-\sin^{2}A)}$ $\sin^{2}A+\cos^{2}A = 1$

7) $\frac{1}{\sin^{2}A-\sin^{4}A}$ Result

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