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White raven [17]
2 years ago
13

Sherman has 5 cats and 5 dogs. He wants to buy a toy for each of his pets. Sherman has $41 to spend on pet toys. How much can he

spend on each pet? Enter the answer as a fraction in simplest form and then as an amount in dollars and cents.
Mathematics
1 answer:
Bumek [7]2 years ago
7 0

Answer: 4.1; $4.10

Step-by-step explanation: He has 10 pets overall. He has 41 dollars, 41 divided by 10 is equal to 4.1; convert that to dollars by making it a fractions of hundreths and add a $.

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Igoryamba

Answer:


Step-by-step explanation:

Collect all variables in one side and numbers on the other side

7w-2w=-3-12

5w=-15

W=-15/5=-3

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3 years ago
Use the information from the analysis and develop a weather report.
madam [21]

Answer:

-3.5°F

Step-by-step explanation:

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2 years ago
Does the point (–9, 8) satisfy the equation y = –x + 1?
Darina [25.2K]

Answer:

1. 3x+3y=9 since it is a coinciding line.It is equivalent because all the terms are multiplied by 3 from the original equation.

2. x-4=3x+4

x=3x+8

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8 0
2 years ago
A couple book a cruise to Alaska that promises to refund 100 per day of rain on the seven day cruise up to a maximum of 300. The
zubka84 [21]

Answer:

the variance of the refund payment to the couple = 9463.394

Step-by-step explanation:

Given that :

A couple book a cruise to Alaska that promises to refund 100 per day of rain on the seven day cruise up to a maximum of 300.

It is possible that the couple won't be able to refund up 100 per day or more than 100 per day.

SO; let assume that the refund payment happens to be 0, 100,200,  300

Let X be the total refund payment on the seven day cruise.

We can say  X = 0, if there is no rain on all 7 days.

P(X = 0) = _nC_x * P^x * (1 - P)n-x

P(X = 0) =  _7C_o * 0.2^0 * (1-0.2)^{7-0

P(X = 0) =1 * 1* (1-0.2)^{7

P(X = 0) =(0.8)^{7

P(X = 0) =0.2097152

If it rains on any one day; then X = 100

P(X = 100) = _nC_x * P^x * (1 - P)n-x

P(X = 100) =  _7C_1 * 0.2^1 * (1-0.2)^{7-1

P(X = 0) =7 * 0.2* (1-0.2)^{6

P(X = 100) =7* 0.2* (0.8)^{6

P(X = 100) =0.3670016

if it rains on any two day  ; then X = 200

P(X = 200) = _nC_x * P^x * (1 - P)n-x

P(X = 200) =  _7C_2 * 0.2^2 * (1-0.2)^{7-2

P(X = 200) =  21 * 0.2^2 * (0.8)^{5

P(X = 200) = 0.2752512

if it rains on any three day or more than that ; then X = 300

P(X \ge 300) = 1 - P(X < 300)  \\ \\ P(X \ge 300) = 1 - [P(X = 0) + P(X = 100) + P(X = 200)] \\ \\ P(X \ge 300) = 1 - [0.2097152 + 0.3670016 + 0.2752512] \\ \\ P(X \ge 300) = 0.148032

Now; we have our probability distribution function as:

P(X = 0) = 0.2097152

P(X = 100) = 0.3670016

P(X = 200) = 0.2752512

P(X = 300) = 0.148032

In order to determine the variance of the refund payment to the couple; we use the formula:

variance of the refund payment to the couple[Var X] =E [X^2] - (E [X])^2

where;

E[X^2]  = \sum x^2 \times p \\ \\ E[X^2]  = 0^2 * 0.2097152 + 100^2 * 0.3670016 + 200^2 * 0.2752512 + 300^2 * 0.148032 \\ \\  E[X^2]  = 0  + 3670.016 + 11010.048+ 13322.88  \\ \\  E[X^2]  =28002.944

(E [X]) = \sum x * p\\ \\  (E [X]) =  0 * 0.2097152 + 100 * 0.3670016 + 200 * 0.2752512 + 300 * 0.148032 \\ \\ (E [X]) = 0 + 36.70016 + 55.05024 + 44.4096\\ \\ (E [X]) = 136.16 \\ \\ (E [X])^2 = 136.16^2 \\ \\ (E [X])^2 = 18539.55

NOW;

the variance of the refund payment to the couple = 28002.944 - 18539.55

the variance of the refund payment to the couple = 9463.394

7 0
2 years ago
What is the slope of a line PARALLEL to the graph?
Contact [7]
(0,-2)(1,1)
slope = (1+2)/(1-0) = 3
parallel lines have same slope

so answer 

<span>C) 3 

--------------
C (0,2) if SF = 1/2
so C'(0. 1)

answer
</span><span>C) (0, 1) </span>
3 0
3 years ago
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