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Romashka [77]
3 years ago
5

you want to compute a 95% confidence interval for the mean of a population with unknown population standard deviation. the sampl

e size is 30. the value of t* you would use for this interval is a) 1.645 b) 1.699 c) 1.96 d) 2.045​

Mathematics
1 answer:
makvit [3.9K]3 years ago
4 0
<h3>Answer: d) 2.045</h3>

Use either a table or a calculator to find this value. The t table should be found in the back of your stats textbook (if you dont have a textbook then you can find a free online t table by searching it out). See the attached image below for how I used a table to get the answer.

If you use a calculator, then you'll use the inverse T function. If n > 30, then you would be able to use a Z distribution instead of a T distribution which would mean that z = 1.96 is the critical value used. But instead, n = 30 does not make n > 30 true. Keep in mind that the degrees of freedom (df) are df = n-1 = 30-1 = 29.

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Can anybody help me?
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f(-2) = 2(-2)² - 8(-2) + 6 = 30

f(-1) = 2(-1)² - 8(-1) + 6 = 16

f(0) = 2(0)² - 8(0) + 6 = 6

f(1) = 2(1)² - 8(1) + 6 = 0

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on a popular fictional game show, contestants are given the opportunity to win money by reaching into a bag after being blindfol
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Construct a probability mass function (pmf) for x, the dollar amount won by a contestant in this game is 1/18.

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  • Probability is the measurement of how likely something is to happen.
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from above total number of chips =4+6+5+2+1 =18

hence Probabilty of win 0 P(0)=4/18

P(1) =6/18

P(5) =5/18

P(10) =2/18

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x     P(x)     xP(x)

0    0.22     0.00

1     0.33      0.33

5     0.28       1.39

10      0.11       1.11

100     0.06      5.56

                       8.39

therefore expeted value =8.39

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brainly.com/question/11234923

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Step-by-step explanation:

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