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ANEK [815]
4 years ago
10

A pair of equations is shown below:

Mathematics
1 answer:
viktelen [127]4 years ago
4 0

Answer:

Part A: t = 2 and y = 7

Part B: Point of intersection is (2,7)

Step-by-step explanation:

Part A: We are given the pair of equations shown below:

y = 8t - 9 ......... (1)

y = 4t - 1 ............ (2)

We can solve those equations by the elimination method.

We have from [equation (1) - equation (2)], 0 = 4t - 8

⇒ t = 2

Therefore, from equation (2), we get y = 4 ×2 - 1 = 7

Hence, t = 2 and y = 7 is the solution of the given pair of equations.

Part B: As equation (1) and equation (2) are two straight lines, so their solution gives the point of intersection of those two lines on the graph.

Therefore, if we plot t along the X-axis and y along the Y-axis then the point of intersection will be (2,7) point. (Answer)

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4 years ago
Im giving 100 Points to anyone who could solve this for me please.
myrzilka [38]

Answer:

AB = 27.2

BC = 33.5

AC = 50.4

∠A = 38°

∠ABC = 112°

Step-by-step explanation:

<u>Trigonometric ratios</u>

\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}

where:

  • \theta is the angle
  • O is the side opposite the angle
  • A is the side adjacent the angle
  • H is the hypotenuse (the side opposite the right angle)

\implies \sf \cos(30^{\circ})=\dfrac{29}{BC}

\implies \sf BC=\dfrac{29}{\cos(30^{\circ})}

\implies \sf BC=\dfrac{58\sqrt{3}}{3}=33.5\:(nearest\:tenth)

\implies \sf \tan(30^{\circ})=\dfrac{BD}{29}

\implies \sf BD=29\tan(30^{\circ})

\implies \sf BD=\dfrac{29\sqrt{3}}{3}

\implies \sf \sin(38^{\circ})=\dfrac{BD}{AB}

\implies \sf AB=\dfrac{\dfrac{29\sqrt{3}}{3}}{\sin(38^{\circ})}

\implies \sf AB=27.2\:(nearest\:tenth)

\implies \sf \tan(38^{\circ})=\dfrac{BD}{AD}

\implies \sf AD=\dfrac{\dfrac{29\sqrt{3}}{3}}{\tan(38^{\circ})}

\implies \sf AD=21.4\:(nearest\:tenth)

\implies \sf AC=AD+DC=21.4+29=50.4

The interior angles of a triangle sum to 180°

⇒ ∠A + 52° + 90° = 180°

⇒ ∠A = 180° - 90° - 52°

⇒ ∠A = 38°

⇒ ∠ABC + 38° + 30° = 180°

⇒ ∠ABC = 180° - 38° - 30°

⇒ ∠ABC = 112°

**I have checked the measures using a graphing programme - see attached**

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