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emmainna [20.7K]
3 years ago
12

What is the resulting equation when the expression for y in the second equation is substituted into the first equation?

Mathematics
1 answer:
Anni [7]3 years ago
5 0

Answer: 3x + 6 -4x = 1

Simplify to -x + 6 = 1 because 3x - 4x = -1x

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71.4285%

Step-by-step explanation:

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What is the midpoint of a segment (-2,-7) and (7,4)
Rasek [7]

\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-7})\qquad
(\stackrel{x_2}{7}~,~\stackrel{y_2}{4})
\qquad
\left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right)
\\\\\\
\left( \cfrac{7-2}{2}~~,~~\cfrac{4-7}{2} \right)\implies \left(\cfrac{5}{2}~,~\cfrac{-3}{2} \right)\implies \left( 2\frac{1}{2}~,~-1\frac{1}{2} \right)

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3 years ago
Anna is x years old and her sister is 5 years older. How old was her sister 5 years ago?
almond37 [142]

Answer:

Step-by-step explanation:

if anna is x years old and her sister is 5 five years older the eqasion would be x=5-5x but there is no further information for the answer. You need to know how old anna is to answer the question. Did you write it correctly

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Consider the function V=g(x), where g(x) =x(6-2x)(8-2x), with x being the length of a cutout in cm and V being the volume of an
Andrej [43]

Answer:

The maximum volume of the open box is 24.26 cm³

Step-by-step explanation:

The volume of the box is given as V=g(x), where g(x)=x(6-2x)(8-2x) and 0\le x\le3.

Expand the function to obtain:

g(x)=4x^3-28x^2+48x

Differentiate  wrt  x to obtain:

g'(x)=12x^2-56x+48

To find the point where the maximum value occurs, we solve

g'(x)=0

\implies 12x^2-56x+48=0

\implies x=1.13,x=3.54

Discard x=3.54 because it is not within the given domain.

Apply the second derivative test to confirm the maximum critical point.

g''(x)=24x-56, g''(1.13)=24(1.13)-56=-28.88\:

This means the maximum volume occurs at x=1.13.

Substitute x=1.13 into g(x)=x(6-2x)(8-2x) to get the maximum volume.

g(1.13)=1.13(6-2\times1.13)(8-2\times1.13)=24.26

The maximum volume of the open box is 24.26 cm³

See attachment for graph.

6 0
3 years ago
Is p(x)= |x| an inverse function
docker41 [41]

Answer:

Step-by-step explanation:

p(x) = |x|

in : R  let : y = |x|

calculate : x

y² = |x| ²

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the inverse : y = x or y = - x

conclusion : the inverse is : g(x) = |x|

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3 years ago
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