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3 years ago

Help me please!!!!!!!!!!!!!!!!

Mathematics

1 answer:

Oxana [17]3 years ago

7 0

Answer:f(x)=x2 +1

Step-by-step explanation:

The one represents C in the standard form and it can also be used to represent graph placement so +1 can also represent the vertex going up 1 on the y

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What is 1/2 of 9? EVERYONE THAT ANSWER THIS QUESTION GETS A WALMART GIFT CARD FOR $5. BUT COME ON, YOU CAN DO ALOT WITH $5.. :p

taurus [48]

4.5 or 4 1/2
you can keep the gift card :p

7 0

3 years ago

Read 2 more answers

The length of a rectangular garden is 30 yards more than the width. The perimeter is 300 yards. Find the length and width

andre [41]

Answer:

60 yards

Step-by-step explanation:

300 = 2(30 + w) + 2(w)

300 = 60 +2w + 2w

300 = 60 + 4w

240 = 4w

60 = w

5 0

3 years ago

A torist walks 10.5 inches in 3 seconds. how far does it walk per second

choli [55]

Divide distance by time:

10.5 inches / 3 seconds = 3.5 inches per second

Answer: 3.5 inches per second

3 0

2 years ago

Read 2 more answers

How do you find DE, Round to nearest 10th

Sergeu [11.5K]

Answer: $DE\approx6.0$

Step-by-step explanation:

Observe in the figure given in the exercise that four right triangles are formed.

In this case you can use the following Trigonometric Identity to solve this exercise:

$cos\alpha=\frac{adjacent}{hypotenuse}$

From the figure you can identify that:

$\alpha =53\°\\\\hypotenuse=10\\\\adjacent=BE=DE$

Then, you can substitute values:

$cos(53\°)=\frac{DE}{10}$

The next step is to solve for DE in order to find its value. This is:

$10*cos(53\°)=DE\\\\DE=6.01$

Finally, rounding the result to the nearest tenth, you get that this is:

$DE\approx6.0$

7 0

3 years ago

On which interval is the average rate of change for bicycle production the greatest? A) 1950 to 1960 B) 1960 to 1970 C) 1970 to

Alborosie

Answer:

D) 1980 to 2000

Step-by-step explanation:

Finding the average rate of change in each interval to determine the greatest one.

Production per interval

1950-1960 = $(21-11) \ million$ = 10 million

1960-1970 = $(41-21)\ million$ = 20 million

1970-1980 = $(71-41)\ million$ = 30 million

1980-2000 = $(161-71)\ million= 90$ million

Rate of change (1950-1960)= $\frac{10}{11} \times 100= 90.90\%$

Rate of change (1960-1970) = $\frac{20}{21} \times 100= 95.23\%$

Rate of change (1970-1980)= $\frac{30}{41} \times 100= 73.17\%$

Rate of change (1980-2000)= $\frac{90}{71} \times 100= 126.76\%$

∴ rate of change between 1980 to 2000 is 126.78%

7 0

3 years ago