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antoniya [11.8K]
3 years ago
7

The LCM of 4 and 7 is ______.

Mathematics
2 answers:
Luden [163]3 years ago
8 0
We should multiply 4 and 7 to find the LCM.
So the LCM will be 4*7 = 28
If it helped please mark as the brainliest answer.
goldfiish [28.3K]3 years ago
5 0

Answer:

28

Step-by-step explanation:

i just did the test

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Help pls! i cant figure it out
shtirl [24]
The answer is 17.5!! goodluck
7 0
3 years ago
Read 2 more answers
Identify the independent and dependent variables. The equation A=25w gives the area A (in square feet) of a rectangular dance fl
kozerog [31]

Answer:

The dependent variable is A

The independent variable is w

Step-by-step explanation:

Given

A = 25w

Required

Identify the variables

In A = 25w

The value of w is independent of the value of A.

In other words:

A derive its own value from w; by multiplying 25 and w.

Take for instance:

w = 3

The value of A would be:

A = 25 * 3

A = 75

Hence:

The dependent variable is A

The independent variable is w

7 0
3 years ago
What is the correct percent of a quiz score of 26 points out of 60
Solnce55 [7]
You just divide 26 by 60 and you get .4333 repeating. To make the decimal a percent you just move the decimal place two places to the right and get about 43%.
5 0
3 years ago
Read 2 more answers
Factorize: (a+1) (a+2)​
eimsori [14]

Answer:

a^2+3a+2

Step-by-step explanation:

(a+1)(a+2)

a(a+2)+1(a+2)

a^2+2a+a+2

a^2+3a+2

5 0
4 years ago
A certain firm has plants A, B, and C producing respectively 35%, 15%, and 50% of the total output. The probabilities of a non-d
Sliva [168]

Answer:

There is a 44.12% probability that the defective product came from C.

Step-by-step explanation:

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

-In your problem, we have:

P(A) is the probability of the customer receiving a defective product. For this probability, we have:

P(A) = P_{1} + P_{2} + P_{3}

In which P_{1} is the probability that the defective product was chosen from plant A(we have to consider the probability of plant A being chosen). So:

P_{1} = 0.35*0.25 = 0.0875

P_{2} is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

P_{2} = 0.15*0.05 = 0.0075

P_{3} is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

P_{3} = 0.50*0.15 = 0.075

So

P(A) = 0.0875 + 0.0075 + 0.075 = 0.17

P(B) is the probability the product chosen being C, that is 50% = 0.5.

P(A/B) is the probability of the product being defective, knowing that the plant chosen was C. So P(A/B) = 0.15.

So, the probability that the defective piece came from C is:

P = \frac{0.5*0.15}{0.17} = 0.4412

There is a 44.12% probability that the defective product came from C.

3 0
4 years ago
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